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Why do we use NaOH solution in the extraction procedure?
NaOH solution is used in the extraction procedure to adjust the pH of the solution, making it more basic. This helps to separate the desired compound from impurities by promoting the formation of a water-insoluble compound that can be easily separated.
How many grams of NaOH(MW40.0) are there in 400.0 ml of a 0.175 M NaOH solution?
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
How much of NaOH were used in the titration?
The amount of NaOH used in a titration depends on the volume and concentration of the NaOH solution used in the experiment. To calculate the exact amount of NaOH used, you would need to know the molarity of the NaOH solution and the volume used in the titration.
How many grams of NaOH are in 350 mL of a 2.5 M of NaOH solution?
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
What is the calculation for 0.1 N naoh solution?
To calculate the concentration of a 0.1 N NaOH solution, you need to know the molar mass of NaOH which is approximately 40 g/mol. Since 1 N solution is equivalent to 1 gram equivalent weight of the solute dissolved in 1 liter of the solution, a 0.1 N NaOH solution would contain 4 g of NaOH per liter of solution.
Why do we use NaOH solution in the extraction procedure?
NaOH solution is used in the extraction procedure to adjust the pH of the solution, making it more basic. This helps to separate the desired compound from impurities by promoting the formation of a water-insoluble compound that can be easily separated.
How many grams of NaOH(MW40.0) are there in 400.0 ml of a 0.175 M NaOH solution?
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
How much of NaOH were used in the titration?
The amount of NaOH used in a titration depends on the volume and concentration of the NaOH solution used in the experiment. To calculate the exact amount of NaOH used, you would need to know the molarity of the NaOH solution and the volume used in the titration.
How many grams of NaOH are in 350 mL of a 2.5 M of NaOH solution?
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
What is the calculation for 0.1 N naoh solution?
To calculate the concentration of a 0.1 N NaOH solution, you need to know the molar mass of NaOH which is approximately 40 g/mol. Since 1 N solution is equivalent to 1 gram equivalent weight of the solute dissolved in 1 liter of the solution, a 0.1 N NaOH solution would contain 4 g of NaOH per liter of solution.
How do you prepare a 6N NaOH solution from a 10N NAOH solution?
To prepare a 6N NaOH solution from a 10N NaOH solution, you would dilute the 10N solution by adding water. Use the dilution formula: C1V1 = C2V2, where C1 is the initial concentration (10N), V1 is the volume of stock solution needed, C2 is the final concentration (6N), and V2 is the final volume of the solution you want to make. Calculate the volume of the 10N solution needed and add water to reach the final desired volume for a 6N NaOH solution.
How to prepare 2N solution of NaOH in 10 ml of water?
To prepare a 2N solution of NaOH in 10 ml of water, you would need to calculate the amount of NaOH needed based on its molecular weight. Once you have determined the amount needed, dissolve it in 10 ml of water to make the solution. Remember to handle NaOH with caution as it is corrosive.
What volume of NaOH solution (in mL) is needed to neutralize a given acid solution?
To determine the volume of NaOH solution needed to neutralize an acid solution, you would need to know the concentration of the acid solution and the volume of the acid solution. Using the equation n1V1 n2V2, where n represents the number of moles and V represents the volume, you can calculate the volume of NaOH solution needed.
What is the molarity of 32.0 of NaOH in 450 of NaOH solution?
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
How do you prepare 0.02m Naoh from 1M Naoh solution?
To prepare 0.02M NaOH from 1M NaOH solution, you will need to dilute the 1M solution. Use the formula: C1V1 = C2V2, where C1 is the concentration of the stock solution (1M), V1 is the volume of the stock solution you will use, C2 is the desired concentration (0.02M), and V2 is the final volume of the diluted solution. Calculate the volume of 1M NaOH solution (V1) needed to make the desired 0.02M concentration and dilute it with water to reach the desired volume (V2).
How an exact of 0.1N solution of NaOH can be prepared?
To prepare a 0.1N solution of NaOH, dissolve 4g of NaOH pellets in enough distilled water to make 1 liter of solution. This will result in a solution with a concentration of 0.1N of NaOH.
Can we make 1N NaOH solution from 0.1N NaOH solution?
Yes, you can make a 1N NaOH solution from a 0.1N NaOH solution by diluting it 10 times. For example, to make 1 liter of 1N NaOH solution, you would mix 100 ml of the 0.1N NaOH solution with 900 ml of water.
