It is possible only if you evaporate the water.
40 grams, this is the 1M NaOH standard laboratory solution.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
Take 10 ml of 1 N NaOH and dilute to 1000 ml with D.I. H2O
Sulphuric Acid requires, I believe 27.2ml to make a 1N solution.
The dilution ratio is 1/10 (1 part 0,1 N solution mixed with 9 parts water).
40 grams, this is the 1M NaOH standard laboratory solution.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
Take 10 ml of 1 N NaOH and dilute to 1000 ml with D.I. H2O
Sulphuric Acid requires, I believe 27.2ml to make a 1N solution.
add 10 grams of NaoH into 1000 ml water, it will give you NaoH of 0.25N. As for making 1N solution you need to disolve 40 grams of NaoH into 1 litre water.
Take specific volume of 3N solution and increase the volume three times by adding distilled water.
The dilution ratio is 1/10 (1 part 0,1 N solution mixed with 9 parts water).
1. Weigh 4 g NaOH. 2. Put this NaOH in a 1 L volumetric flask. 3. Add slowly 100 mL distilled water and stir. 4. Put the flask in a thermostat at 20 0C and maintain for 1 hour. 5. Add distilled water up to the mark. Stir vigorously. 6. Standardize the solution by titration with oxalic acid, potassium hydrogen phtalate, etc. 7. Transfer the solution in a bottle and apply a label (date, name of the operator, name of the solution, normality).
Prions are only destroyed by:• incineration• autoclaving in 1N NaOH
One Mole of Sodium Hydroxide NaOH= 40.00g/l =1N (8.0g NaOH in 100.0ml of water)= 2N NaOH or (80g of NaOH in 1L of water)= 2N NaOH
There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution
1N HCl is also 1M HCl because it is mono-protic. Therefore 36.5 g of HCl is required per liter or 3.65%. Simply take 100 g of 37% HCl and make up to the 1 liter mark on the volumetric flask. Check the value by titration against 1M NaOH. It should be perfect. If very slightly strong dilute very slightly (calculate) with water and re-standardize.