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How do you prepare 2N H2SO4 and 2M H2SO4?
MW of H2SO4 is 98.08. 2M = 2 x 98.08 in 1 L of water (1 gram=1 ml). Take 500 ml water in a 1 L measuring cylinder. Add 196.16 ml slowly along the side into water in the measuring cylinder. Use 50 ml pipette with automated pipettor. If needed you may want to keep the cylinder in ice to take care of the heat generated. Then make up to volume to 1 L with water. Eq. wt for H2SO4 = 98.08/2 = 49.039. SO for 2N solution, 2 eq.wt in 1 L. 98.08 ml in 1 L water adopting the method cited above.
How do you prepare the 1.25 percent H2SO4 solution?
Concentrated H2SO4 is 96 %.( In laboratory ) As density of concentrated H2SO4 is 1.84gm/ml we will need this number as well, and as the atomic mass of H2SO4 is 98.08,as it is dibasic for normality it is 49 hence, Calculation=((96/100)(1000)(1.84))/49=36.04 If H2SO4 concentrated is 36.04 M then for make a 1L solution of 1M H2SO4 (36.04)X (x) = 1X(1) x = 1 X(1) / (36.04) x=0.0277gm/ml of water x = 27.7 mL of 36M H2SO4 per liter Hence for 1N H2SO4 dissolve 27.7ml of it to 1000ml of solvent(Water) that means for 0.1 N H2SO4 2.77 ml of it to 1000mL of solvent.
How many milliliters of 0.200M H2SO4 will neutralize 40.0 mL of 1.50M KOH?
Let's solve this problem without using specific numbers as that's more instructive (and won't give away an answer to someone's homework problem).The question is:What volume Vacid of strong diprotic acid solution of molarity Macid is needed to neutralize a volume Vbase strong base solution of molarity Mbase?So, Macid, Vbase, and Mbase are known and we are asked to find Vacid.A strong base of the form BOH will completely dissociate in solution into B+ and OH- ions, so Mbase is the same as MOH- in this problem.A strong diprotic acid of the form AH2 will lose both of its protons in the presence of OH- ions to form A2+ and two H+ ions, so Macid is half of MH+ in this problem.Neutralization is the process of mixing an acidic solution with a basic solution in proportion such that the number of OH- ions in the basic solution is equal to the number of H+ ions in the acidic solution. To get the number, you must multiply the ions' molarity times there volumes.So, we need:MH+·Vacid = MOH-·Vbaseor2·Macid·Vacid = Mbase·Vbase (since Macid is half of MH+ and Mbase equals MOH-)solve for Vacid to obtainVacid = (Mbase·Vbase)/(2·Macid)
How do you make 0.02N sulfuric acid solution?
I would like to dilute some 5N sulfuric acid with water, and make 0.1N sulfuric acid solution. I want 1000ml of 0.1N . I think it's a 50 to 1 ration, but just want to make sure. <Volume of concentrated> x <Concentration of Concentrated> = <Volume of dilute> x <Concentration of dilute> Therefore, <Volume of concentrated> = <Volume of dilute> x <Concentration of dilute> / <Concentration of dilute> = 1000 mL x 0.1 N / 5N = 20 mL. Meaning: Dilute 20 mL of the 5N H2SO4 to 1000 mL in a volumetetric flask will give you 1000 mLs of 0.1 N H2SO4 (aq.).
What is chemical equation when acetamide react with sulphuric acid?
Acetamide has a chemical formula of C2H5NO, and sulphuric acid is H2SO4. Their reaction is C2H5NO + H2SO4 <--> C2H6NO + HSO4. Note however, that the conjugate acid of acetamide may take two forms due to the non bonding electrons on the oxygen and nitrogen atoms of acetamide.
How do you prepare 2N H2SO4 and 2M H2SO4?
MW of H2SO4 is 98.08. 2M = 2 x 98.08 in 1 L of water (1 gram=1 ml). Take 500 ml water in a 1 L measuring cylinder. Add 196.16 ml slowly along the side into water in the measuring cylinder. Use 50 ml pipette with automated pipettor. If needed you may want to keep the cylinder in ice to take care of the heat generated. Then make up to volume to 1 L with water. Eq. wt for H2SO4 = 98.08/2 = 49.039. SO for 2N solution, 2 eq.wt in 1 L. 98.08 ml in 1 L water adopting the method cited above.
Is ionization endothermic or exothermic?
It is exothermic. Take for example H2SO4 H2SO4 -> H+ + HSO4- This is very exothermic
How do you prepare the 1.25 percent H2SO4 solution?
Concentrated H2SO4 is 96 %.( In laboratory ) As density of concentrated H2SO4 is 1.84gm/ml we will need this number as well, and as the atomic mass of H2SO4 is 98.08,as it is dibasic for normality it is 49 hence, Calculation=((96/100)(1000)(1.84))/49=36.04 If H2SO4 concentrated is 36.04 M then for make a 1L solution of 1M H2SO4 (36.04)X (x) = 1X(1) x = 1 X(1) / (36.04) x=0.0277gm/ml of water x = 27.7 mL of 36M H2SO4 per liter Hence for 1N H2SO4 dissolve 27.7ml of it to 1000ml of solvent(Water) that means for 0.1 N H2SO4 2.77 ml of it to 1000mL of solvent.
How many milliliters of 0.200M H2SO4 will neutralize 40.0 mL of 1.50M KOH?
Let's solve this problem without using specific numbers as that's more instructive (and won't give away an answer to someone's homework problem).The question is:What volume Vacid of strong diprotic acid solution of molarity Macid is needed to neutralize a volume Vbase strong base solution of molarity Mbase?So, Macid, Vbase, and Mbase are known and we are asked to find Vacid.A strong base of the form BOH will completely dissociate in solution into B+ and OH- ions, so Mbase is the same as MOH- in this problem.A strong diprotic acid of the form AH2 will lose both of its protons in the presence of OH- ions to form A2+ and two H+ ions, so Macid is half of MH+ in this problem.Neutralization is the process of mixing an acidic solution with a basic solution in proportion such that the number of OH- ions in the basic solution is equal to the number of H+ ions in the acidic solution. To get the number, you must multiply the ions' molarity times there volumes.So, we need:MH+·Vacid = MOH-·Vbaseor2·Macid·Vacid = Mbase·Vbase (since Macid is half of MH+ and Mbase equals MOH-)solve for Vacid to obtainVacid = (Mbase·Vbase)/(2·Macid)
How much 100x TAE buffer will it take to make 500ml of 1x TAE solution?
to make 500ml of 1x TAE solution we have to take 5ml of 100x TAE solution. mix it in 495 ml of deionized water.
How do you make 0.02N sulfuric acid solution?
I would like to dilute some 5N sulfuric acid with water, and make 0.1N sulfuric acid solution. I want 1000ml of 0.1N . I think it's a 50 to 1 ration, but just want to make sure. <Volume of concentrated> x <Concentration of Concentrated> = <Volume of dilute> x <Concentration of dilute> Therefore, <Volume of concentrated> = <Volume of dilute> x <Concentration of dilute> / <Concentration of dilute> = 1000 mL x 0.1 N / 5N = 20 mL. Meaning: Dilute 20 mL of the 5N H2SO4 to 1000 mL in a volumetetric flask will give you 1000 mLs of 0.1 N H2SO4 (aq.).
Is an isotonic solution or hypotonic solution safest for a patient?
An isotonic solution is safest for a patient because it has the same concentration of solutes as the body's cells and does not cause them to shrink or swell. A hypotonic solution, on the other hand, could cause cells to take in too much water and burst.
Does it take longer to saturate a heated solution than a cold solution?
No, a heated solution will saturate faster.
What is chemical equation when acetamide react with sulphuric acid?
Acetamide has a chemical formula of C2H5NO, and sulphuric acid is H2SO4. Their reaction is C2H5NO + H2SO4 <--> C2H6NO + HSO4. Note however, that the conjugate acid of acetamide may take two forms due to the non bonding electrons on the oxygen and nitrogen atoms of acetamide.
How do you prepare 60 percent sulphuric acid solution?
Well, darling, to prepare a 60% sulfuric acid solution, you simply mix 60 parts of concentrated sulfuric acid with 40 parts of water. Just make sure to add the acid to the water slowly to avoid any explosive reactions - safety first, honey! And voila, you've got yourself a potent solution ready to go.
Calculate the concentration of 98 percent sulfuric acid by mass 1.84 g ml density?
To calculate the concentration of sulfuric acid, we first need to convert the density to units of g/mL. Since the density is already given as 1.84 g/mL, for a 98% solution, we take 98% of the density to find the mass of sulfuric acid in 1 mL. This would be 1.84 g/mL * 0.98 = 1.8032 g/mL.
Why might temperature of water increase when a solution forms?
A solution can take in energy, which is heat.
