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MW of H2SO4 is 98.08. 2M = 2 x 98.08 in 1 L of water (1 gram=1 ml). Take 500 ml water in a 1 L measuring cylinder. Add 196.16 ml slowly along the side into water in the measuring cylinder. Use 50 ml pipette with automated pipettor. If needed you may want to keep the cylinder in ice to take care of the heat generated. Then make up to volume to 1 L with water. Eq. wt for H2SO4 = 98.08/2 = 49.039. SO for 2N solution, 2 eq.wt in 1 L. 98.08 ml in 1 L water adopting the method cited above.
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∙ 14y ago
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∙ 9y agoA 4N H2SO4 solution is equivalent to a 2M H2SO4 solution. In chemistry, N is normality, which is a measure of concentration equal to the gram equivalent weight per liter solution. For a 2M H2SO4 solution, the normality will be 4N because there will be 4 moles of H+ ions per liter of solution.
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∙ 10y agoSince 1 mole of H2SO4 (sulfuric acid) produces 2 moles of hydrogen ions, 1 N H2SO4 would be 0.5 M (because 0.5 moles of H2SO4 would produce 1 mole of H+ ions.) So, you would use 49g H2SO4 in 1 liter of water, which is a 0.5 M solution.
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∙ 14y agohow to prepare 2 N H2So4
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How do you prepare 2.5N h2so4?
how 2.5N H2SO4 prepared from concentrated H2SO4
What volume of 6.40 m h2so4 is needed to prepare 455.0ml of a solution that is 0.700m in h2so4?
You need 49,8 mL H2SO4 6,4M.
What mass of h2so4 would required to prepare 750 ml of a 0.15m h2so4 solution?
h
How to prepare 250ml of a 2m solution of potassium chloride?
111.72
How do you prepare 7 N sulfuric acid?
7n h2so4
2m - n - m - 2n?
0
What is 2m plus 2n plus p?
It can't be simplified any further so it is:2m + 2n + p
If two odd numbers are added together what is the result?
Two odd numbers added together will always be an even number. I'll show how: Let M and N be any two integers. 2M is even, and 2N is even. So (2M +1) is an odd number, and (2N + 1) is an odd number. (2M +1) + (2N +1) = 2M + 1 + 2N +1 = 2M + 2N + 2 = 2(M + N + 1), which is even.
Is 2m-2n equals 0 linear?
Yes.
How do you prepare 2.5N h2so4?
how 2.5N H2SO4 prepared from concentrated H2SO4
Is the sum of an even whole number and an odd whole number always odd?
Yes --------------------------------------------- Let n be an integer. Then 2n is an even number Let m be an integer. Then 2m is an even number and 2m + 1 is an odd number. Then: even + odd = (2n) + (2m + 1) = (2n + 2m) + 1 = 2(n + m) + 1 = 2k + 1 (where k = m + n) which is an odd number.
Why does an odd number times an odd number equal an odd number?
Let's do some algebra. Assume that "m" and "n" are any integers. An even number is divisible by 2, so 2m or 2n would be even. An odd number is one that is not divisible by 2, so 2m + 1, or 2n + 1, are odd numbers.Multiply those two odd numbers together: (2m+1)(2n+1) = 4mn + 2m + 2n + 1. Since the first three parts are even, the added 1 at the end makes the result odd.
How do you solve L equals 2M plus 2N for N?
N=l-m
Why do you get an odd number when you multiply two odd numbers?
Let one odd number be "2m + 1", the other odd number "2n + 1" (where "m" and "n" are integers). All odd numbers have this form. If you multiply this out, you get (2m+1)(2n+1) = 4mn + 2m + 2n + 1. Since each of the first three parts is even, the "+1" at the ends converts the result into an odd number.
How is the sum of three odd numbers always odd?
Algebraically, this can be seen: An odd number is one more than an even number, and all multiples of 2 are even numbers. Let three odd numbers be (2n + 1), (2m + 1) & (2k + 1) for some n, m & k. Adding them gives: (2n + 1) + (2m + 1) + (2k + 1) = 2n + 2m + 2k + 1 + 1 + 1 = 2n + 2m + 2k + 2 + 1 = 2(n + m + k + 1) + 1 which is one more than an even number - an odd number.
Why odd number minus a odd number even?
Every odd number leaves a remainder of 1 when divided by 2. Therefore, every odd number is of the form 2k +1 where k is some integer.Suppose 2m + 1 and 2n + 1 are two odd numbers.Then (2m + 1) - (2n + 1) = 2m + 1 - 2n - 1 = 2m - 2n = 2*(m - n)By the closure property of integers under addition (and subtraction), m and n being integers implies than (m - n) is an integer. Therefore 2*(m - n) is an even integer.
What volume of 6.40 m h2so4 is needed to prepare 455.0ml of a solution that is 0.700m in h2so4?
You need 49,8 mL H2SO4 6,4M.
