How many milliliters of 0.200M H2SO4 will neutralize 40.0 mL of 1.50M KOH?

Answer 1

Let's solve this problem without using specific numbers as that's more instructive (and won't give away an answer to someone's homework problem).

The question is:
What volume Vacid of strong diprotic acid solution of molarity Macid is needed to neutralize a volume Vbase strong base solution of molarity Mbase?


So, Macid, Vbase, and Mbase are known and we are asked to find Vacid.


A strong base of the form BOH will completely dissociate in solution into B+ and OH- ions, so Mbase is the same as MOH- in this problem.


A strong diprotic acid of the form AH2 will lose both of its protons in the presence of OH- ions to form A2+ and two H+ ions, so Macid is half of MH+ in this problem.


Neutralization is the process of mixing an acidic solution with a basic solution in proportion such that the number of OH- ions in the basic solution is equal to the number of H+ ions in the acidic solution. To get the number, you must multiply the ions' molarity times there volumes.


So, we need:
MH+·Vacid = MOH-·Vbase


or


2·Macid·Vacid = Mbase·Vbase (since Macid is half of MH+ and Mbase equals MOH-)


solve for Vacid to obtain

Vacid = (Mbase·Vbase)/(2·Macid)

Answer 2

H2SO4 + 2KOH --> K2SO4 + 2H2O ... balanced equation (note it takes 2 KOH for each 1 H2SO4)
moles KOH present = 0.040 L x 1.50 mol/L = 0.06 moles (it will take 1/2 of this or 0.03 moles H2SO4)
volume H2SO4 needed: (x L)(0.200 mol/L) = 0.03 moles
x = 0.15 L = 150 ml of H2SO4 needed

Answer 3

To determine the volume of H2SO4 needed to neutralize KOH, you must first calculate the moles of KOH present (mol = M x L). Then, use the mole ratio from the balanced chemical equation (2 moles of KOH to 1 mole of H2SO4) to determine the moles of H2SO4 required. Finally, use the molarity of H2SO4 to calculate the volume needed (V = mol/M).

Answer 4

It would require more HCL than H2SO4, since the valency factor {n-factor} of h2so4 is 2, while that of HCL is 1.

Answer 5

22.1 mL

Answer 6

20mL's

Answer 7

150