How do you prepare the 1.25 percent H2SO4 solution?

Answer 1

Concentrated H2SO4 is 96 %.( In laboratory )

As density of concentrated H2SO4 is 1.84gm/ml we will need this number as well, and as the Atomic Mass of H2SO4 is 98.08,as it is dibasic for normality it is 49

hence,

Calculation=((96/100)(1000)(1.84))/49=36.04

If H2SO4 concentrated is 36.04 M then for make a 1L solution of 1M H2SO4

(36.04)X (x) = 1X(1)

x = 1 X(1) / (36.04)

x=0.0277gm/ml of water

x = 27.7 mL of 36M H2SO4 per liter

Hence for 1N H2SO4 dissolve 27.7ml of it to 1000ml of solvent(Water)

that means for 0.1 N H2SO4 2.77 ml of it to 1000mL of solvent.

Answer 2

To prepare a 1.25% sulfuric acid (H2SO4) solution, you would mix 1.25 grams of sulfuric acid with 100 mL of water. This would give you a solution where the mass of sulfuric acid is 1.25% of the total solution mass. Be sure to carefully add the acid to the water to prevent splattering or spilling.

Answer 3

- transfer approx. 75 mL of distilled (deionized) water in a clean and dried 100 mL volumetric flask

- weight the flask

- add 0,4902 g of concentrated sulfuric acid

- stirr vigourosly for mixing

- put the flask in a thermostat at 20 0C

- after the flask with the solution reach 20 0C add easily distilled (deionized) water to the mark

- again stirr vigourosly

- transfer the solution from the volumetric flask in another glass bottle

- label the bottle (type of solution, concentration, date, operator)

Answer 4

Normality=Molarity x N-factor.

=>Molarity=Normality/N-factor.

N-factor for H2SO4 is 2.

So,

Molarity=0.02/2=0.01 M

This means we have to dissolve 0.01moles of H2SO4 in 1L of water t prepare a 0.02 N solution.

0.01 M H2SO4 = 98g/0.01=.98g

We dissolve .98g H2SO4 1L of water to get the desired solution

Answer 5

The preparation of 0.5 M sulfuric acid (H2SO4) depends on what you start with and what volume of 0.5 M solution you want. If you begin with concentration H2SO4, which is usually 36.8 N, then this is equal to 18.4 M. To prepare 1 liter of 0.5 M, you would proceed as follows:(x L)(18.4 M) = (1 L)(0.5 M) and x = 0.027 L = 27 mls.

So, take 27 mls of concentrated H2SO4 and dilute to a final volume of 1000 ml.

Answer 6

Assuming the conc. H2SO4 is 18 M (or close to it), then use V1M1 = V2M2 and to make, say 1 liter,(x ml)(18 M) = (1000 ml)(0.1 M) and x = 5.56 mls of conc. H2SO4 diluted to a final volume of 1 liter to make 0.1 M.

Answer 7

H2SO4 has a molar mass of 98.1 grams per mole. To prepare a 0.5 M solution, add 49.05 grams of sulfuric acid per liter of water.

Answer 8

take 14

ml of conc

sulfuric acid and add to volumetric flask contain 400 ml dist. water and complete to 1000 ml with water

Answer 9

suppose you have conc. sulfuric acid 96% sp.gr 1.84

so 1.25% sulfuric equal to 1/96*100=1.3

1.3ml of conc. sulfuric per 100ml water so 13 ml per liter

Answer 10

.98