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How many moles of sodium hydroxide are in 40 grams of sodium hydroxide?
Wiki User
∙ 13y ago
1
Wiki User
∙ 13y ago
To find the number of moles in 40 grams of sodium hydroxide, you first need to calculate the molar mass of NaOH. The molar mass of NaOH is about 40 g/mol. Then, you divide the given mass by the molar mass to get the number of moles. So, 40 grams divided by 40 g/mol is equal to 1 mole of NaOH.
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How many grams of sodium hydroxide are there in 0.150 mol?
To find the grams of sodium hydroxide in 0.150 mol, first calculate the molar mass of sodium hydroxide, which is approximately 40 g/mol. Then, multiply the molar mass by the number of moles: 40 g/mol x 0.150 mol = 6 grams of sodium hydroxide.
How many grams of sodium hydroxide are present in 675 mL of a 0.500M solution?
To calculate the grams of sodium hydroxide present in the solution, first calculate the number of moles using the formula: moles = Molarity (M) x Volume (L). Then, use the molar mass of sodium hydroxide (NaOH) to convert moles to grams. The molar mass of NaOH is 40 g/mol. Thus, in this case, you have 0.3375 moles of NaOH and if you convert this to grams, it would be 13.5 grams.
How many grams are in a 6.94 mole sample of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams per mole. Therefore, a 6.94 mole sample of sodium hydroxide would contain approximately 278 grams (6.94 moles x 40 grams/mole).
How many grams of sodium hydroxide are needed to make 250. ml of a 7.80 M solution?
To find the grams of sodium hydroxide needed, you first calculate the moles required using the molarity equation (moles = Molarity x Volume). Then, convert moles to grams using the molar mass of sodium hydroxide, which is 40 g/mol. Finally, the calculation would be: (7.80 mol/L) x 0.250 L x 40 g/mol = 78 grams of sodium hydroxide.
How many moles of sodium hydroxide will react with 17 moles of sulfuric acid?
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
How many moles are in 8 grams of sodium hydroxide?
0.2 mol
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
You would have 1.5 moles of sodium hydroxide. This is calculated by dividing the mass of sodium hydroxide by its molar mass: 60 grams / 40 grams/mole = 1.5 moles.
How many grams of sodium hydroxide are there in 0.150 mol?
To find the grams of sodium hydroxide in 0.150 mol, first calculate the molar mass of sodium hydroxide, which is approximately 40 g/mol. Then, multiply the molar mass by the number of moles: 40 g/mol x 0.150 mol = 6 grams of sodium hydroxide.
How many grams of sodium hydroxide are present in 675 mL of a 0.500M solution?
To calculate the grams of sodium hydroxide present in the solution, first calculate the number of moles using the formula: moles = Molarity (M) x Volume (L). Then, use the molar mass of sodium hydroxide (NaOH) to convert moles to grams. The molar mass of NaOH is 40 g/mol. Thus, in this case, you have 0.3375 moles of NaOH and if you convert this to grams, it would be 13.5 grams.
How many grams are in a 6.94 mole sample of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams per mole. Therefore, a 6.94 mole sample of sodium hydroxide would contain approximately 278 grams (6.94 moles x 40 grams/mole).
How do you the stoichiometry problem 2 NaOH plus H2SO4---2 H2O plus Na2SO4how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excessofsulfur?
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
How many grams of sodium hydroxide are needed to make 250. ml of a 7.80 M solution?
To find the grams of sodium hydroxide needed, you first calculate the moles required using the molarity equation (moles = Molarity x Volume). Then, convert moles to grams using the molar mass of sodium hydroxide, which is 40 g/mol. Finally, the calculation would be: (7.80 mol/L) x 0.250 L x 40 g/mol = 78 grams of sodium hydroxide.
How many moles of sodium hydroxide will react with 17 moles of sulfuric acid?
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
How many moles of sodium sulphate can be formed from two moles of sodium hydroxide?
No amount of sodium sulphate can be formed from sodium hydroxide alone, because sodium sulfate contains sulfur and sodium hydroxide does not. By neutralization with sulphuric acid, one formula unit of sodium sulphate can be formed from two moles of sodium hydroxide, according to the equation 2 NaOH + H2SO4 -> Na2SO4 + 2 H2O.
How many grams are in four tenths moles of sodium chloride?
23.3772 grams are there in four tenths moles of sodium chloride
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
First, calculate the number of moles of nitric acid present in 3.50 L of 0.700 M solution. Since nitric acid is a diprotic acid, the mole ratio with sodium hydroxide is 1:2. Then, use the mole ratio to determine the number of moles of sodium hydroxide needed to neutralize the nitric acid. Finally, convert the moles of sodium hydroxide to grams using its molar mass.
How many grams of solute are required to make a 918 mL solution of sodium hydroxide with a concentration of 0.4922 M?
Molarity = moles of solute/Liters of solution ( 918 ml = 0.918 liters )rearranged algebraically,moles of solute = Liters of solution * Molaritymoles of NaOH = (0.918 l)(0.4922 M)= 0.45184 moles NaOH=======================so,0.45184 moles NaOH (39.998 grams/1 mole NaOH)= 18.1 grams sodium hydroxide needed============================
