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How many moles of sodium sulphate can be formed from two moles of sodium hydroxide?
No amount of sodium sulphate can be formed from sodium hydroxide alone, because sodium sulfate contains sulfur and sodium hydroxide does not. By neutralization with sulphuric acid, one formula unit of sodium sulphate can be formed from two moles of sodium hydroxide, according to the equation 2 NaOH + H2SO4 -> Na2SO4 + 2 H2O.
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How many moles are in 8 grams of sodium hydroxide?
0.2 mol
How many moles of sodium hydroxide will be produced from the complete reaction of 15.0 g sodium?
Sodium reacts with water. 0.652 NaOH moles will form.
When calculating the number of moles of calcium hydroxide formed from each mole of sodium hydroxide in the balanced reaction CaCl2 plus 2 NaOH and reg Ca(OH)2 plus 2 NaCl the best conversion factor to?
In the balanced reaction between calcium chloride (CaCl2) and sodium hydroxide (NaOH) to form calcium hydroxide (Ca(OH)2) and sodium chloride (NaCl), the stoichiometry indicates that 1 mole of CaCl2 reacts with 2 moles of NaOH to produce 1 mole of Ca(OH)2. Therefore, the best conversion factor to use when calculating the number of moles of calcium hydroxide formed from each mole of sodium hydroxide is ( \frac{1 , \text{mol Ca(OH)}_2}{2 , \text{mol NaOH}} ). This factor shows that for every 2 moles of NaOH used, 1 mole of Ca(OH)2 is produced.
What is the name of the salt that is formed from oxalic acid?
Oxalic acid forms an oxalate salt when reacted with two equivalents of base - the name of the salt depends on the composition of the base. For example, if one mole of oxalic acid reacts with two moles of sodium hydroxide (NaOH), then one mole of sodium oxalate and two moles of water are formed. (Sodium oxalate is Na2C2O4.) If one mole of oxalic acid reacted with two moles of ammonia (NH3), then one mole of ammonium oxalate ((NH4)2C2O4) and two moles of water are formed.
How many moles are there in 8 g sodium hydroxide?
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
How many moles of sodium hydroxide are formed when 46 g of sodium react with water?
First construct a a balanced equation for the reaction : 2Na + 2H2O --> 2NaOH + H2 From the equation, we know that the ratio of Sodium(Na) to the ratio of Sodium Hydroxide(NaOH) is the same. Ar of Na = 23g/mol Number of moles = mass / Ar = 46g / 23g/mol = 2mol (moles of Na used) Since ratio of Na to NaOH is the same, therefore there are also 2 moles of NaOH formed.
Determine the number of moles of sodium hydroxide produced when 2 moles of sodium and 3 mol of water react to form soduim hydroxide and hydrogen gas?
Na +H2O -> NaOH +(1/2)H2 Every mole of Sodium requires one mole of water to make one mole of Sodium Hydroxide. So two moles of Sodium will produce two moles of Sodium Hydroxide. If there are three moles of water in the initial reaction then there will be one mole of water left over after reacting with two moles of Sodium. This reaction will produce half a mole of hydrogen gas.
How many moles of sodium hydroxide will react with 17 moles of sulfuric acid?
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
How do you the stoichiometry problem 2 NaOH plus H2SO4---2 H2O plus Na2SO4how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excessofsulfur?
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
How many moles of sodium in 5.25 mole of Na2SO4?
There are 10.5 moles of sodium in 5.25 moles of Na2SO4 because there are 2 sodium atoms in one formula unit of Na2SO4.
What is the mass in grams of 25 mol of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams/mol. To find the mass of 25 moles of NaOH, you would multiply the number of moles by the molar mass: 25 mol * 40 g/mol = 1000 grams. So, the mass of 25 moles of sodium hydroxide is 1000 grams.
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
What is the molarity of a 3 sodium hydroxide solution?
A 3 M sodium hydroxide solution means there are 3 moles of sodium hydroxide dissolved in 1 liter of solution.
How many moles in 20g of sodium hydroxide?
To determine the number of moles in 20g of sodium hydroxide, you need to divide the given mass by the molar mass of sodium hydroxide. The molar mass of NaOH is 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). So, 20g NaOH / 40 g/mol = 0.5 moles of sodium hydroxide.
What is the balanced equation for sodium hydroxide and copper III chloride?
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
What is the balanced equation when iodine reacts with sodium hydroxide?
6NaOH + 3I2 = 5NaI + NaIO3 + 3H2O Six moles of sodium hydroxide and three moles of diatomic iodine yield five moles of sodium iodide, one mole of sodium iodate, and three moles of water. Cheers!
How many moles are in 8 grams of sodium hydroxide?
0.2 mol
