A 3 M sodium hydroxide solution means there are 3 moles of sodium hydroxide dissolved in 1 liter of solution.
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
The molarity of Na+ ions in a 0.25 M solution of Na3PO4 is 0.75 M. This is because each formula unit of Na3PO4 dissociates into 3 Na+ ions in solution. Therefore, the concentration of Na+ ions is three times the molarity of the Na3PO4 solution.
When you mix iron(III) nitrate with sodium hydroxide, it forms a precipitate of iron(III) hydroxide and sodium nitrate in the solution. Iron(III) hydroxide is a brownish solid that can be formed as a precipitate in this reaction.
The products of the reaction between sodium hydroxide and iron(III) sulfate are iron(III) hydroxide and sodium sulfate. This reaction forms a precipitate of iron(III) hydroxide while sodium sulfate remains in solution.
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
To prepare a 3% solution of sodium hydroxide, you can dissolve 3 grams of sodium hydroxide pellets in 100 mL of distilled water. Ensure proper safety precautions are taken when handling sodium hydroxide as it is a caustic substance that can cause burns.
the molar mass of sodium hydroxide is 40g/mol mike
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, there are 2 moles of sodium chloride in 250 cm^3, which is equivalent to 0.25 L. Therefore, the molarity of the solution is 8 M (2 moles / 0.25 L).
The molarity of Na+ ions in a 0.25 M solution of Na3PO4 is 0.75 M. This is because each formula unit of Na3PO4 dissociates into 3 Na+ ions in solution. Therefore, the concentration of Na+ ions is three times the molarity of the Na3PO4 solution.
When you mix iron(III) nitrate with sodium hydroxide, it forms a precipitate of iron(III) hydroxide and sodium nitrate in the solution. Iron(III) hydroxide is a brownish solid that can be formed as a precipitate in this reaction.
The products of the reaction between sodium hydroxide and iron(III) sulfate are iron(III) hydroxide and sodium sulfate. This reaction forms a precipitate of iron(III) hydroxide while sodium sulfate remains in solution.
Calcium Hydroxide & Ammonia Solution & Sodium Hydroxide. Are the Common Alkalis you find in a Lab
Phosphoric Acid dissociates to give off 3H+ ions, meaning that one mole of Phosphoric acid reacts with three mols of sodium hydroxide. Using the equation n = c x v n = 0.1 x 0.05 =0.005 mols of OH ions in the solution therefore there are 0.005/3 = 0.00167 So the volume of phosphoric acid - v = n/c v = 0.00167/0.2 v = 0.00835 l = 8.4ml of Phosphoric Acid reacts completely with Sodium hydroxide
Add sodium hydroxide solution; aluminium hydroxide will dissolve but Mg(OH)2 remain.
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
When aqueous Ferric chloride is allow to react with Sodium hydroxide the reddish brown ppts. of ferric hydroxide are formed. FeCl3 (aq.) + 3NaOH = Fe(OH)3 + 3NaClThey form precipitates of Ferric hydroxide.