Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
First we calculate the mol of sodium carbonate, but we need to calculate of its formula weight. Formula weight of Na2CO3 = ( 2 x Ar Na) + (1 x Ar C) + ( 3 x Ar O) ...
Get moles silver nitrate. 255 grams AgNO3 (1 mole AgNO3/169.91 grams) = 1.5008 moles AgCO3 --------------------------------Now; Molarity = moles of solute/Liters of solution ( 1500 ml = 1.5 Liters ) Molarity = 1.5008 moles AgNO3/1.5 Liters = 1.00 M AgNO3 ---------------------
n=CV/1000 Where n = number of moles, C= Molarity concentration of the solution, and V= volume of the solution in milliliter's We are given, n=0.150, V=8.16 liters(8160 milliliters)and C is not given. Solving for C from the equation above we get: C=(n*1000)/V C= (0.150*1000)/8160 C= 0.018 The molarity of the solution is 0.018
In moles of substance dissolved in 1 L of water -Apex
1500 md/day (19-50yr) 1300 mg/day (51-70yr) 1200 mg/day (>70 yr)
1.5 liter * 2.45 moles/liter = 3.675 molesMolar mass of magnesium sulfate is 120.3676 g/mol3.675x120.3676 =442.35093g
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
Molarity is moles per litre. You need to divide the moles by 1500 and multiply by 1000. 5.6/1500*1000 is 3.73333 molar.
Get moles silver nitrate. 255 grams AgNO3 (1 mole AgNO3/169.91 grams) = 1.5008 moles AgCO3 --------------------------------Now; Molarity = moles of solute/Liters of solution ( 1500 ml = 1.5 Liters ) Molarity = 1.5008 moles AgNO3/1.5 Liters = 1.00 M AgNO3 ---------------------
n=CV/1000 Where n = number of moles, C= Molarity concentration of the solution, and V= volume of the solution in milliliter's We are given, n=0.150, V=8.16 liters(8160 milliliters)and C is not given. Solving for C from the equation above we get: C=(n*1000)/V C= (0.150*1000)/8160 C= 0.018 The molarity of the solution is 0.018
0.27 M
In moles of substance dissolved in 1 L of water -Apex
2608 mg of salt is 1500 mg of sodium i.e. half a teaspoon
1500 mg
1200 Actual calculation is (1500*((100-20)/100)
If the sodium content of sodium chloride is 39,66583 %, 1 500 kg NaCl contain: 1 500 X 0,3966583 = 594,99 kg sodium.
1500-2300 mg
Yes, the amount of heat required to produce it though is over 1500 degrees kelvin.