0
What is the molarity of a solution if 255 grams AgNO3 is dissolved in 1500 mL of solution?
Get moles silver nitrate.
255 grams AgNO3 (1 mole AgNO3/169.91 grams)
= 1.5008 moles AgCO3
--------------------------------Now;
Molarity = moles of solute/Liters of solution ( 1500 ml = 1.5 Liters )
Molarity = 1.5008 moles AgNO3/1.5 Liters
= 1.00 M AgNO3
---------------------
What else can I help you with?
What is the molarity of a solution in which 0.45 grams of sodium nitrate are dissolved in 265 mL of solution?
To calculate the molarity, first convert the mass of sodium nitrate to moles using its molar mass. Then, divide the number of moles by the volume of solution in liters (265 mL = 0.265 L) to get the molarity. The molarity of the solution is about 0.68 M.
What is molarity of 2m acetic acid?
(.05)X(grams of total solution) = grams of acetic acid (grams of acetic acid)/ (mol. wt. of acetic acid(=60g/mol)) = mol. acetic acid (mol. acetic acid)/ (Liters of total solution) = molarity(M)
What is the molarity of a solution made by dissolving 25 grams of Mg in excess NaOH solution?
The molarity of the solution is 0.5 M.
How do you prepare a molar solution?
To prepare a molar solution, you need to measure the correct amount of solute (substance being dissolved) in grams and dissolve it in a specific volume of solvent (usually water) to reach the desired molarity. Molarity is the number of moles of solute per liter of solution. You can use the formula: Molarity (M) moles of solute / liters of solution.
What is the molarity of an aqueous solution that contains 12.2 grams of SrCl2 dissolved in 2500 milliliters of solution?
The molar mass of SrCl2 is 158.52 g/mol. First, convert the volume to liters (2500 mL = 2.5 L). Next, calculate the number of moles of SrCl2 in 12.2 grams. Finally, divide the number of moles by the volume in liters to find the molarity.
25.5 grams of lead fluoride in .088L of solution would have molarity?
The concentration of a solution can be expressed in many ways. One of them is as the molarity of the solution. A solution with molarity equal to one has one mole of the solute dissolved in every liter of the solutions
How many grams of AgNO3 are required to make 500.0 mL of a 0.10 M solution?
Ah, what a lovely question! To make a 0.10 M solution of AgNO3 in 500.0 mL, we can use the formula: moles = molarity x volume (in liters). First, convert 500.0 mL to liters by dividing by 1000. Then, multiply the molarity (0.10 M) by the volume in liters to find the moles of AgNO3 needed. Finally, convert moles to grams using the molar mass of AgNO3. Happy calculating!
What is the molarity of a silver nitrate that contains 42.5g AgNO3 in 100mL of solution?
First we need to convert grams(g) to moles(mol) and mL to L, since M(molarity)=mol/L.Ag=107.868N=14O=16 x3=48AgNO3 =169.868 g/mol42.5g x 1 mol/169.868g = .25mol AgNO3100mL x 10-3 L/ 1mL = .1LM=mol/L.25mol/.1L = 2.5M AgNO3
Molarity of 734 grams of lithium sulfate are dissolved to make 2500ml of solution?
To find the molarity of the solution, first calculate the number of moles of lithium sulfate in 734g. Then, divide the moles by the volume of solution in liters to get the molarity. Remember to convert grams to moles using the molar mass of lithium sulfate (Li2SO4).
What is the molarity of a solution in which 0.45 grams of sodium nitrate are dissolved in 265 mL of solution?
To calculate the molarity, first convert the mass of sodium nitrate to moles using its molar mass. Then, divide the number of moles by the volume of solution in liters (265 mL = 0.265 L) to get the molarity. The molarity of the solution is about 0.68 M.
What is molarity of 2m acetic acid?
(.05)X(grams of total solution) = grams of acetic acid (grams of acetic acid)/ (mol. wt. of acetic acid(=60g/mol)) = mol. acetic acid (mol. acetic acid)/ (Liters of total solution) = molarity(M)
What is the molarity of a solution that contains 1.1 of lithium in 0.5 liters of solution?
If 1,1 is grams the molarity is 0,317.
What is the molarity of a solution made by dissolving 25 grams of Mg in excess NaOH solution?
The molarity of the solution is 0.5 M.
How do you prepare a molar solution?
To prepare a molar solution, you need to measure the correct amount of solute (substance being dissolved) in grams and dissolve it in a specific volume of solvent (usually water) to reach the desired molarity. Molarity is the number of moles of solute per liter of solution. You can use the formula: Molarity (M) moles of solute / liters of solution.
What is the molarity of a solution that contains 12.2 grams of SrCl2 dissolved in 2500 milliliters of solution?
Molarity = moles of solute/liters of solution 2500 milliliters = 2.5 liters ------------------------------------ 12.2 grams SrCl2 (1 mole SrCl2/158.52 grams) = 0.07696 moles strontium chloride -------------------------------------------------------------------------------------------------------- so, Molarity = 0.07696 moles SrCl2/2.5 liters = 3.07 X 10 -2 M SrCl2 -------------------------------------
How does the amount of solute moles and grams relate to the density and molarity of the solution?
Increasing the amount of the solute in the solution the molarity and the density of this solution increases.
What is the molarity of an aqueous solution that contains 12.2 grams of SrCl2 dissolved in 2500 milliliters of solution?
The molar mass of SrCl2 is 158.52 g/mol. First, convert the volume to liters (2500 mL = 2.5 L). Next, calculate the number of moles of SrCl2 in 12.2 grams. Finally, divide the number of moles by the volume in liters to find the molarity.
