Start by looking up atomic masses of Na, N and O.
Convert grams to kilograms.
Molarity = moles solute/ Liters solution
copper sulphate solution-blue sodium chloride (salt) solution-clear sodium nitrate solution- white to clear sodium sulphate solution- white copper sulphate solution-blue sodium chloride (salt) solution-clear sodium nitrate solution- white to clear sodium sulphate solution- white
Sodium nitrate (NaNO3) is very soluble in water.
The molarity of a solution made by dissolving 23,4 g of sodium sulphate in enough water to make up a 125 mL solution is 1,318.
0.01 mole
It is a solution. A solution is a type of mixture in which a solute is dissolved in a solvent. A solution is a homogeneous mixture. In the case of an aqueous solution of sodium nitrate, the sodium nitrate is the solute and the water is the solvent.
4m
A solution of sodium nitrate is homogeneous.
Molarity = moles solute/ Liters solution
copper sulphate solution-blue sodium chloride (salt) solution-clear sodium nitrate solution- white to clear sodium sulphate solution- white copper sulphate solution-blue sodium chloride (salt) solution-clear sodium nitrate solution- white to clear sodium sulphate solution- white
Sodium nitrate (NaNO3) is very soluble in water.
In chemistry, the concentration of a substance in solution is determined by molarity, which is symbolized by "M". This indicates the number of moles of a substance dissolved in one liter of a solvent (usually water). For example: - 1 mole of sodium chloride = 58 grams - If 116 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 2-molar (2 M) solution of sodium chloride. - If 232 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 4-molar (4 M) solution of sodium chloride.
This molarity is 0,207 mol.
Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
The molarity is 0,125 M.
The molarity of a solution made by dissolving 23,4 g of sodium sulphate in enough water to make up a 125 mL solution is 1,318.
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.