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How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
How many grams of sodium are there in 10.0 grams of sodium sulfate?
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
How many sodium ions are there in .482 mole of sodium sulfate Na2SO4?
There are 2 moles of sodium ions in 1 mole of sodium sulfate (Na2SO4). Therefore, in 0.482 moles of sodium sulfate, there would be 0.482 x 2 = 0.964 moles of sodium ions. Finally, multiplying by Avogadro's number (6.022 x 10^23) gives approximately 5.80 x 10^23 sodium ions.
How many moles of atoms are contained in 2.88g na2 so4?
Full formal set up. 2.88 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(6.022 X 1023/1 mole Na2SO4)(1 mole Na2SO4 atoms/6.022 X 1023) = 0.020 moles of sodium sulfate atoms ------------------------------------------------------( you can see the last two steps are superfluous )
The hydrate sodium sulfate on heating the hydrate how many moles of water should be driven off per mole of hydrate?
For sodium sulfate decahydrate (Na2SO4·10H2O), on heating, 10 moles of water molecules will be driven off per mole of the hydrate. Each formula unit of the hydrate contains 10 water molecules.
When 0.5 moles of Na2SO4 is dissolved in water how many moles of sodium ions are present?
Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.
How many grams are in 3.6 moles of sodium sulfate?
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
How many grams of sodium are in 0.820 moles of Na2SO4?
To find the grams of sodium in 0.820 moles of Na2SO4, first calculate the molar mass of Na2SO4: 2(Na) + 1(S) + 4(O) = 2(23) + 32 + 4(16) = 142 g/mol. Since each mole of Na2SO4 contains 2 moles of Na atoms, the molar mass of Na in Na2SO4 is 46 g/mol. Therefore, in 0.820 moles of Na2SO4, there are 0.820 moles * 2 moles Na * 46 g/mol = 75.32 grams of sodium.
How many grams of sodium are there in 10.0 grams of sodium sulfate?
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
What is the concentration of Na2SO4 solution prepared by dissolving 5.35 g of Na2SO4 in sufficient water to give 330 ml of solution?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
How many sodium ions are there in .482 mole of sodium sulfate Na2SO4?
There are 2 moles of sodium ions in 1 mole of sodium sulfate (Na2SO4). Therefore, in 0.482 moles of sodium sulfate, there would be 0.482 x 2 = 0.964 moles of sodium ions. Finally, multiplying by Avogadro's number (6.022 x 10^23) gives approximately 5.80 x 10^23 sodium ions.
How many grams of solid barium sulfate form when 22.6 mL of 0.160 M barium chloride reacts with 54.6 mL of 0.055 M sodium sulfate?
Balanced equation first. BaCl2 + Na2SO4 -> 2NaCl + BaSO4 22.6 ml BaCl2 = 0.0226 liters 54.6 ml Na2SO4 = 0.0546 liters 0.160 M BaCl2 = moles BaCl2/0.0226 liters = 0.00362 moles BaCl2 0.055 M Na2SO4 = moles Na2SO4/0.0546 liters = 0.0030 moles Na2SO4 The ratio of BaCl2 to Na2SO4 is one to one, so either mole count wull drive this reaction. Use 0.0003 moles Na2SO4 0.0030 moles Na2SO4 (1 mole BaSO4/1 mole Na2SO4)(233.37 grams/1 mole BaSO4) = 0.700 grams of BaCO4 produced
How many atoms of sodium are in 0.250 moles of Na2SO4?
There are 3.01 x 10^23 atoms of sodium in 0.250 moles of Na2SO4. This is calculated by multiplying the Avogadro's number (6.022 x 10^23 atoms/mol) by the stoichiometric ratio (2 sodium atoms per molecule of Na2SO4).
If you have 1 mole of NaCl how many moles of sodium did you have?
1 mole
How many moles of sodium are needed to make 3.6 moles of sodium chloride?
One mole of sodium chloride is composed of one mole of sodium atoms. Therefore, 3.6 moles of sodium chloride would require 3.6 moles of sodium.
How many moles of atoms are contained in 2.88g na2 so4?
Full formal set up. 2.88 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(6.022 X 1023/1 mole Na2SO4)(1 mole Na2SO4 atoms/6.022 X 1023) = 0.020 moles of sodium sulfate atoms ------------------------------------------------------( you can see the last two steps are superfluous )
