1 mole
Every formula unit of sodium chloride has one sodium atom. Therefore, there are 4.0 moles of sodium ions in 4.0 moles of NaCl.
There are 1 mole of sodium ions in 1 mole of NaCl, as there is one sodium ion for each chlorine ion in the compound. Therefore, in 2 moles of NaCl, there are 2 moles of sodium ions, which is equal to 2 x 6.022 x 10^23 sodium ions.
1.946 moles NaCl (58.44 grams/1 mole NaCl) = 113.7 grams sodium chloride ======================
In 1 mole of NaCl, there is 1 mole of sodium ions. Therefore, 3.0 moles of NaCl will contain 3.0 moles of sodium ions. Since 1 mole contains 6.022 x 10^23 particles, 3.0 moles will contain 1.807 x 10^24 sodium ions.
1 mole NaCl = 58.44g 0.1601mol NaCl x 58.44g NaCl/mol NaCl = 9.35g NaCl
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
There will be 6.022 x 10^23 sodium ions in 2.00 mol of NaCl. This is because one mole of NaCl contains one mole of sodium ions, and Avogadro's number (6.022 x 10^23) represents the number of entities in one mole of a substance.
Divide it by molar mass. So the answer is 0.518 mol
To find the number of moles in 72.0g of sodium chloride, you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass by the molar mass: 72.0g / 58.44 g/mol ≈ 1.23 moles of NaCl.
There are 5 formula masses of Na in 5 formula masses of NaCl, as indicated by the fact that the symbol for sodium has no explicit subscript in the formula of NaCl. Neither sodium nor sodium chloride has moles in the strictest sense, since neither of them is covalently bonded.
3.0 moles NaCl [1 mole Na(+)/1 mole Cl(-)][6.022 X 10^23/ 1 mole Na(+)] = 1.8 X 10^24 sodium ions
Formal set up. 10 grams sodium chloride (1 mole NaCl/58.44 grams)(1 mole Na/1 mole NaCl)(6.022 X 1023/1 mole Na) = 1.0 X 1023 atoms of sodium --------------------------------------