72.0 grams NaCl (1 mole NaCl/58.44 grams)
= 1.2 moles of sodium chloride
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
When 4 moles of sodium react with oxygen, 2 moles of sodium oxide are produced (according to the balanced equation). Therefore, when 10 moles of sodium react, 5 moles of sodium oxide will be produced.
There are 3 moles of sodium represented in one mole of sodium phosphate (Na3PO4). This is because the subscript 3 in Na3PO4 indicates that there are 3 sodium ions for every molecule of sodium phosphate.
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
By stoichiometry, 2 moles of sodium carbonate will produce 2 moles of sodium chloride. The molar mass of sodium chloride is approximately 58.44 g/mol, so 2 moles would weigh about 116.88 grams.
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
The answer is 0,111 moles.
Every formula unit of sodium chloride has one sodium atom. Therefore, there are 4.0 moles of sodium ions in 4.0 moles of NaCl.
Sodium in its elemental form is just sodium metal, Na. Thus assuming that the sample of sodium is pure, there are 2.50 moles of sodium in a 2.50mol sample.
One mole of sodium chloride is composed of one mole of sodium atoms. Therefore, 3.6 moles of sodium chloride would require 3.6 moles of sodium.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
The answer is 0,175 moles.
There are 10.5 moles of sodium in 5.25 moles of Na2SO4 because there are 2 sodium atoms in one formula unit of Na2SO4.
55.0 moles of sodium are equal to 1 264,44 g.
Sodium has 12 neutrons. Chloride ion has 18 neutrons. In a formula unit, NaCl has 30 neutrons.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
When 4 moles of sodium react with oxygen, 2 moles of sodium oxide are produced (according to the balanced equation). Therefore, when 10 moles of sodium react, 5 moles of sodium oxide will be produced.