Sodium in its elemental form is just sodium metal, Na. Thus assuming that the sample of sodium is pure, there are 2.50 moles of sodium in a 2.50mol sample.
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
The answer is 48,17 L.
To calculate the number of moles in a solution, use the formula: moles = Molarity x Volume (in liters). First, convert the volume from milliliters to liters by dividing by 1000 (250 mL = 0.25 L). Then, plug the values into the formula: moles = 1.20 mol/L x 0.25 L = 0.30 moles of sodium chloride.
The answer is 0,111 moles.
Every formula unit of sodium chloride has one sodium atom. Therefore, there are 4.0 moles of sodium ions in 4.0 moles of NaCl.
One mole of sodium chloride is composed of one mole of sodium atoms. Therefore, 3.6 moles of sodium chloride would require 3.6 moles of sodium.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
There are 10.5 moles of sodium in 5.25 moles of Na2SO4 because there are 2 sodium atoms in one formula unit of Na2SO4.
The answer is 0,175 moles.
55.0 moles of sodium are equal to 1 264,44 g.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
When 4 moles of sodium react with oxygen, 2 moles of sodium oxide are produced (according to the balanced equation). Therefore, when 10 moles of sodium react, 5 moles of sodium oxide will be produced.