Balanced equation first.
BaCl2 + Na2SO4 -> 2NaCl + BaSO4
22.6 ml BaCl2 = 0.0226 liters
54.6 ml Na2SO4 = 0.0546 liters
0.160 M BaCl2 = moles BaCl2/0.0226 liters
= 0.00362 moles BaCl2
0.055 M Na2SO4 = moles Na2SO4/0.0546 liters
= 0.0030 moles Na2SO4
The ratio of BaCl2 to Na2SO4 is one to one, so either mole count wull drive this reaction. Use 0.0003 moles Na2SO4
0.0030 moles Na2SO4 (1 mole BaSO4/1 mole Na2SO4)(233.37 grams/1 mole BaSO4)
= 0.700 grams of BaCO4 produced
yes
If both of the compounds named in the question are in solution in water, barium sulfate will precipitate. If both are solids when mixed, there will usually be no reaction.
The net ionic equation for formation of a precipitate [note correct spelling] when sodium sulfate and barium chloride solutions are mixed is Ba+2 + SO4 -2 -> BaSO4 (s)
whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed. whencalcium chloride reacts with barium nitrate calcium nitrate and barium chloride wil be formed.
Sodium sulfate is highly soluble in water, but insoluble in most organic solvents. If you want to increase its solubility in water (as for any salt), you can heat the solution or remove one of the products (sodium ions or sulfate ions) from solution. I can't think of any insoluble sodium salts, but barium sulfate (BaSO4) is insoluble in water. Thus, adding barium chloride (or some other soluble barium salt) will remove sulfate from the equilibrium (due to BaSO4 precipitation) and increase the solubility of sodium sulfate.
add water to dissolve the sodium chloride, filter and you can collect the barium sulfate behind the filter paper
Barium chloride can be precipitated wit a sulfate; barium sulfate is then filtrated.
By filtration barium sulfate being insoluble in water.
Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.
The white solid precipitated when an aqueous solution of barium chloride is mixed with an aqueous solution of sodium sulfate is named "barium sulfate" and has the formula BsSO4.
yes
precipitate of balium sulphate and solution of sodium chloride is formed!
1. Put the mixture of powders in a beaker and add water. 2. Stir vigorously. Sodium chloride is dissolved, barium sulfate not. 3. Filter to separate sodium chloride solution (passes the filter) from barium sulfate as a solid on the filter.
The balanced equation for sodium sulfate (Na2SO4) plus barium chloride (BaCl2) yielding barium sulfate (BaSO4) and sodium chloride (NaCl) is: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
Barium sulfate is much less soluble in water than either of sodium chloride and sodium chloride. When mixed, the solubility of the barium sulfate is exceeded. The barium sulfate then precipitates as fine solids, which remain suspended but scatter light to produce the milky look. Added: Na+ (sodium ion) and Cl- (chloride ion) don't react, Only Ba2+ and SO42- do so by forming precipitate: SO42- + Ba2+ --> (BaSO4)s
This equation is BaCl2 (aq) + Na2SO4 (aq) -> 2 NaCl (aq) + BaSO4 (s).
sodium carbonate and barium chloride react to form sodium chloride and barium carbonate Na2CO3 +BaCl2 -------> 2NaCl +BaCO3