precipitate of balium sulphate and solution of sodium chloride is formed!
add water to dissolve the sodium chloride, filter and you can collect the barium sulfate behind the filter paper
Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.
The balanced equation for sodium sulfate (Na2SO4) plus barium chloride (BaCl2) yielding barium sulfate (BaSO4) and sodium chloride (NaCl) is: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
Barium sulfate is much less soluble in water than either of sodium chloride and sodium chloride. When mixed, the solubility of the barium sulfate is exceeded. The barium sulfate then precipitates as fine solids, which remain suspended but scatter light to produce the milky look. Added: Na+ (sodium ion) and Cl- (chloride ion) don't react, Only Ba2+ and SO42- do so by forming precipitate: SO42- + Ba2+ --> (BaSO4)s
The precipitate will be barium sulfate. The reaction is as follows:BaCl2(aq) + Na2SO4(aq) ==> 2NaCl(aq) + Ba(SO4)(s)
Barium chloride can be precipitated wit a sulfate; barium sulfate is then filtrated.
add water to dissolve the sodium chloride, filter and you can collect the barium sulfate behind the filter paper
By filtration barium sulfate being insoluble in water.
Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.
The white solid precipitated when an aqueous solution of barium chloride is mixed with an aqueous solution of sodium sulfate is named "barium sulfate" and has the formula BsSO4.
1. Put the mixture of powders in a beaker and add water. 2. Stir vigorously. Sodium chloride is dissolved, barium sulfate not. 3. Filter to separate sodium chloride solution (passes the filter) from barium sulfate as a solid on the filter.
Barium sulfate is much less soluble in water than either of sodium chloride and sodium chloride. When mixed, the solubility of the barium sulfate is exceeded. The barium sulfate then precipitates as fine solids, which remain suspended but scatter light to produce the milky look. Added: Na+ (sodium ion) and Cl- (chloride ion) don't react, Only Ba2+ and SO42- do so by forming precipitate: SO42- + Ba2+ --> (BaSO4)s
The balanced equation for sodium sulfate (Na2SO4) plus barium chloride (BaCl2) yielding barium sulfate (BaSO4) and sodium chloride (NaCl) is: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
sodium carbonate and barium chloride react to form sodium chloride and barium carbonate Na2CO3 +BaCl2 -------> 2NaCl +BaCO3
The insoluble salt barium sulfate is obtained.
The precipitate will be barium sulfate. The reaction is as follows:BaCl2(aq) + Na2SO4(aq) ==> 2NaCl(aq) + Ba(SO4)(s)
If both of the compounds named in the question are in solution in water, barium sulfate will precipitate. If both are solids when mixed, there will usually be no reaction.