6NaOH + 3I2 = 5NaI + NaIO3 + 3H2O
Six moles of sodium hydroxide and three moles of diatomic iodine yield five moles of sodium iodide, one mole of sodium iodate, and three moles of water.
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C6H5NH2 + NaOH = C6H4NaO + NH4
2Na + 2H2O = 2NaOH + H2
you have to write... 2KI + Cl2 = 2KCl + I2
Ba(OH)2(hydroxide) + H2SO4(acid) ==> BaSO4(salt) + 2H2O(water)
2KI + Cl2 = 2KCl + I2
Perchloric acid is a strong acid. Sodium hydroxide is a strong base. HClO4(aq) + NaOH(aq) ---> Na+(aq) + ClO4-(aq) + H2O(l) This is a balanced chmical reaction since the products and reacts have a 1:1 ratio.
2Na + 2H2O = 2NaOH + H2
you have to write... 2KI + Cl2 = 2KCl + I2
Ba(OH)2(hydroxide) + H2SO4(acid) ==> BaSO4(salt) + 2H2O(water)
The balanced equation for the reaction between calcium hydroxide and hydrochloric acid is: Ca(OH)2 + 2HCl → CaCl2 + 2H2O In this reaction, calcium hydroxide (Ca(OH)2) reacts with hydrochloric acid (HCl) to produce calcium chloride (CaCl2) and water (H2O). The equation is balanced with 1 molecule of calcium hydroxide reacting with 2 molecules of hydrochloric acid to produce 1 molecule of calcium chloride and 2 molecules of water.
Sodium reacts with water to form sodium hydroxide and hydrogen. The balanced equation is 2Na + 2H2O --> 2NaOH + H2.
2KI + Cl2 = 2KCl + I2
potassium iodide
The answer is Cr(OH)3(s)+3HNO2(aq)-->Cr(NO2)3(aq)+3H2O(l)
An explosion will occur.
This equation is I2 (s) + 4 Cl2 (gas) => 2 ICl4 (s).
Chromium don't react with water.
Perchloric acid is a strong acid. Sodium hydroxide is a strong base. HClO4(aq) + NaOH(aq) ---> Na+(aq) + ClO4-(aq) + H2O(l) This is a balanced chmical reaction since the products and reacts have a 1:1 ratio.