Ba(OH)2(hydroxide) + H2SO4(acid) ==> BaSO4(salt) + 2H2O(water)
Ba(OH)2+Na2SO4 =BaSO4+2NaOH
2KOH + Ba(NO3)2 -----> 2KNO3 + Ba(OH)2
Ba(NO3)2 + 2NaOH → Ba(OH)2 + 2NaNO3Barium nitrate + sodium hydroxide → barium hydroxide + sodium nitrate
(NH4)2SO4(aq) + BaCl2(aq) → 2NH4Cl(aq) + BaSO4(s). Barium sulfate is the precipitate.
BaSO4 + 2H2O --> Ba(OH)2 + H2SO4 There is now one Barium, one Sulfate, two hydroxides, and two oxygens on either side of the arrow. The above reaction would make sense if barium sulfate was soluble in water... but it is not. In fact, it is so insoluble in water that there is no reaction.
Ba + SO4 will give you BaSO4 Ba + Br will give you BaBr2The first equation is barium sulfate and the second one is barium bromide.
Barium sulphate to barium sulphate is NO CHANGE!
The equation is , Ba(OH)2 + 2HCl = BaCl2 + 2H2O
This equation is Ba(OH)2 + H2SO4 -> BaSO4 + H2O.
BaCl2+K2SO4=2KCl+BaSO4
The balanced equation for sodium sulfate (Na2SO4) plus barium chloride (BaCl2) yielding barium sulfate (BaSO4) and sodium chloride (NaCl) is: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
The barium ion in barium hydroxide and sulfate ion in sulfuric acid combine to form barium sulfate, which is insoluble in water.
(NH4)2SO4 + Ba(NO3)2 -> BaSO4 + 2NH4NO3
BaSO4 + 2CaCl2 --> Ba(Cl2)2 + Ca2SO4
This equation is BaCl2 (aq) + Na2SO4 (aq) -> 2 NaCl (aq) + BaSO4 (s).
2KOH + Ba(NO3)2 -----> 2KNO3 + Ba(OH)2
Ba(OH)2 + 2HNO3 -------> Ba(NO3)2 +2H2O