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To find the grams of sodium hydroxide in 0.150 mol, first calculate the molar mass of sodium hydroxide, which is approximately 40 g/mol. Then, multiply the molar mass by the number of moles: 40 g/mol x 0.150 mol = 6 grams of sodium hydroxide.
To find the number of moles in 40 grams of sodium hydroxide, you first need to calculate the molar mass of NaOH. The molar mass of NaOH is about 40 g/mol. Then, you divide the given mass by the molar mass to get the number of moles. So, 40 grams divided by 40 g/mol is equal to 1 mole of NaOH.
To calculate the grams of sodium hydroxide present in the solution, first calculate the number of moles using the formula: moles = Molarity (M) x Volume (L). Then, use the molar mass of sodium hydroxide (NaOH) to convert moles to grams. The molar mass of NaOH is 40 g/mol. Thus, in this case, you have 0.3375 moles of NaOH and if you convert this to grams, it would be 13.5 grams.
Using stoichiometry, we can calculate that 27 grams of sodium metal reacting with water produces 40 grams of sodium hydroxide. Since 40 grams of sodium hydroxide were produced, this correlates to 27 grams of sodium being consumed. Therefore, the water added should be the difference between the initial weight of sodium (27 grams) and the weight of sodium left (0 grams) after the reaction, resulting in 27 grams of water being added.
To find the grams of sodium hydroxide needed, you first calculate the moles required using the molarity equation (moles = Molarity x Volume). Then, convert moles to grams using the molar mass of sodium hydroxide, which is 40 g/mol. Finally, the calculation would be: (7.80 mol/L) x 0.250 L x 40 g/mol = 78 grams of sodium hydroxide.
155.2 g
0.2 mol
To find the grams of sodium hydroxide in 0.150 mol, first calculate the molar mass of sodium hydroxide, which is approximately 40 g/mol. Then, multiply the molar mass by the number of moles: 40 g/mol x 0.150 mol = 6 grams of sodium hydroxide.
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
The iron(III) hydroxide is not soluble in water and doesn't react with sodium chloride.
To determine the number of grams of pure sodium hydroxide present in a solution with a known volume, you need to know the concentration of the solution in g/ml. Then you can use the formula: grams = concentration (g/ml) x volume (ml)
There are approximately 6 x 10^22 atoms in a 12.0 gram sample of sodium.
98g
262 - 266
262 - 266
To find the amount of sodium hydroxide needed to react with 150g of phosphoric acid, you first need to determine the balanced chemical equation between sodium hydroxide and phosphoric acid. From there, you can use stoichiometry to calculate the amount of sodium hydroxide needed.
To find the number of moles in 40 grams of sodium hydroxide, you first need to calculate the molar mass of NaOH. The molar mass of NaOH is about 40 g/mol. Then, you divide the given mass by the molar mass to get the number of moles. So, 40 grams divided by 40 g/mol is equal to 1 mole of NaOH.