Molarity = moles of solute/Liters of solution ( 24.5 mL = 0.0245 L)
Rearranged,
moles of solute = Liters of solution * Molarity
Moles NaOH = (0.0245 L)(0.130 M NaOH)
= 3.19 X 10 -3 moles NaOH
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0.75 moles in 30.0g of NaOH.
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
Molarity = moles of solute/liters of solution ( 15ml = 0.015 liters ) 2.9 M NaOH = moles NaOH/0.015 liters = 0.0435 moles of NaOH
You need 2,4 g NaOH (0,06 moles).
The same number of moles for each.
0.75 moles in 30.0g of NaOH.
M = g/L 20 = g/0.05 20 * .05 = g 1.0 = g of solute
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
208g NaOH
The number of moles is 0,0038.
Molarity = moles of solute/liters of solution ( 15ml = 0.015 liters ) 2.9 M NaOH = moles NaOH/0.015 liters = 0.0435 moles of NaOH
Molecular mass of NaOH= 40.0 grams9.40 grams / (40.0 grams) = .235 moles NaOH
You need 2,4 g NaOH (0,06 moles).
The same number of moles for each.
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH