0.75 moles in 30.0g of NaOH.
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
To find the number of moles of NaOH in 8 g, first calculate the molar mass of NaOH (sodium hydroxide) which is approximately 40 g/mol (sodium - 23 g/mol, oxygen - 16 g/mol, hydrogen - 1 g/mol). Then, divide the given mass (8 g) by the molar mass to get the number of moles. So, 8 g / 40 g/mol = 0.2 moles of NaOH.
To find the number of moles in 80.0g of NaOH, divide the given mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40.0 g/mol (sodium - 22.99 g/mol, oxygen - 16.00 g/mol, hydrogen - 1.01 g/mol). Therefore, there are 2.00 moles of NaOH in 80.0g.
To find the number of moles in 12.0 g of NaOH, you first need to calculate its molar mass. The molar mass of NaOH (sodium hydroxide) is 39.997 g/mol. Next, you divide the given mass by the molar mass: 12.0 g / 39.997 g/mol ≈ 0.30 moles of NaOH.
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
To find the number of moles of NaOH in 8 g, first calculate the molar mass of NaOH (sodium hydroxide) which is approximately 40 g/mol (sodium - 23 g/mol, oxygen - 16 g/mol, hydrogen - 1 g/mol). Then, divide the given mass (8 g) by the molar mass to get the number of moles. So, 8 g / 40 g/mol = 0.2 moles of NaOH.
To find the number of moles in 9.4 g of NaOH, you first need to calculate the molar mass of NaOH (22.99 g/mol for Na, 15.999 g/mol for O, and 1.008 g/mol for H). Add these together to get 39.997 g/mol for NaOH. Next, divide the given mass by the molar mass to get the number of moles: 9.4 g / 39.997 g/mol ≈ 0.235 moles of NaOH.
To find the number of moles in 80.0g of NaOH, divide the given mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40.0 g/mol (sodium - 22.99 g/mol, oxygen - 16.00 g/mol, hydrogen - 1.01 g/mol). Therefore, there are 2.00 moles of NaOH in 80.0g.
To find the number of moles in 12.0 g of NaOH, you first need to calculate its molar mass. The molar mass of NaOH (sodium hydroxide) is 39.997 g/mol. Next, you divide the given mass by the molar mass: 12.0 g / 39.997 g/mol ≈ 0.30 moles of NaOH.
To calculate the number of moles of NaOH, we use the formula: moles = molarity x volume (in liters). First, convert 20 mL to liters (0.02 L). Then, use the formula to find: moles = 0.5 mol/L x 0.02 L = 0.01 moles of NaOH present in 20 ml of 0.5M NaOH.
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
To convert grams of NaOH to moles, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). Thus, 20 grams of NaOH is equivalent to 0.5 moles (20 g / 40 g/mol).
2.00 M NaOH = 2 moles NaOH/litermolar mass NaOH = 40 g/mole2 moles/liter x 40 g/mole = 80 g/liter(x L)(80 g/L) = 32.0 gx = 0.4 liters = 400 mls needed