M = g/L 20 = g/0.05 20 * .05 = g 1.0 = g of solute
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
Since NaOH and HBr react in a 1:1 ratio, the moles of NaOH needed to titrate HBr can be calculated. Moles of NaOH = moles of HBr. Next, use the concentration and volume of HBr to find the moles present. Finally, use the concentration of NaOH to calculate the volume needed. In this case, approximately 2.41 mL of 0.305M NaOH would be needed.
To determine the grams of KHP required, you first need to calculate the number of moles of NaOH present in the 50 mL solution. Then, using the balanced chemical equation of the titration between NaOH and KHP, you can find the mole ratio. From the mole ratio and the moles of NaOH, you can calculate the moles of KHP needed and then convert that to grams of KHP.
Moles/Liters=Molarity (M) therefore: Molarity*Liters=moles Since you were given milliliters, you must first convert your volume to liters for the equation to be accurate. 2.2M*.065L=moles=.143 moles NaOH
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution cheers :D The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution.
208g NaOH
Molarity = moles of solute/Liters of solution ( 24.5 mL = 0.0245 L)Rearranged,moles of solute = Liters of solution * MolarityMoles NaOH = (0.0245 L)(0.130 M NaOH)= 3.19 X 10 -3 moles NaOH==================
The number of moles is 0,0038.
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
To determine the number of moles in 4g of sodium hydroxide (NaOH), divide the mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40g/mol (Na = 23g/mol, O = 16g/mol, H = 1g/mol). Therefore, 4g of NaOH is equal to 0.1 moles.
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
1st Get the balanced equation NaOH + HCl -> NaCl + H2O Find the number of moles in HCl; n = cv n = 0.46x0.61 n = 0.2806 moles the number of moles of HCl and NaOH is the same so 0.2806moles will be needed
The number of moles of NaOH used in the titration process can be calculated by dividing the volume of NaOH solution used by the molarity of the NaOH solution.
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
When titrating NaOH with KHP (potassium hydrogen phthalate), the number of moles of NaOH will be equal to the number of moles of KHP at the equivalence point. This is because the reaction is stoichiometric, with one mole of NaOH reacting with one mole of KHP.