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The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution cheers :D The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution.
What else can I help you with?
How many mL of 1m NaOH would it take to neutralize 100 mL of an unknown HCL concentration?
You would need to know the concentration of the unknown HCl solution in order to determine the volume of 1M NaOH needed to neutralize it using the equation: M1V1 = M2V2. Without the concentration of HCl, it is not possible to calculate the volume of NaOH required for neutralization.
How many ml of 250 M NaOH are required to neutralize 30.4 ml of 152 M HCl?
To neutralize the acid, we need to use the same number of moles of base. First, calculate the number of moles of HCl using its concentration and volume. Then, use the mole ratio from the balanced equation to find the required volume of NaOH. Convert the volume to mL.
How many milliliters of 0.400 M NaOH are required to completely neutralize 20.00 mL of 0.200 M HCl?
To neutralize HCl with NaOH, the mole ratio is 1:1. So, the moles of HCl are 0.200 M x 0.020 L = 0.004 moles. Since NaOH and HCl react in a 1:1 ratio, we need 0.004 moles of NaOH. Using the molarity formula, we find that we need 0.010 L or 10.00 mL of 0.400 M NaOH.
How Many milliliters of 0.258 M NaOH are required to complétely neutrilize 2.00 g of aceitic acid HC2H3O2?
To find the volume of 0.258 M NaOH needed to neutralize 2.00 g of acetic acid (HC2H3O2), you can use the molar ratio between NaOH and acetic acid. First, determine the moles of acetic acid using its molar mass. Then, use the mole ratio from the balanced chemical equation to find moles of NaOH required. Finally, use the concentration of NaOH to find the volume needed.
How many NaOH required to neutralize complitly4.9 gms of H2SO4?
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
How many microliters are in twenty mL?
5ml = 1 teaspoon 20ml = 4 teaspoons
How many ml of 0.10 m naoh solution are needed to neutralize 15 ml of 0.20 m h3po4 solution?
90. mL NaOH, remember there are two sig figs in this problem not one, hence the decimal point after the 90.
How many microliters are in 20mL?
20000 microlitres
20 mls equals how many ounces?
20mL is 0.67628 US fluid ounces.
How many microliters are in 20 milliliter?
20mL is 20,000µL (microliters)
How many 20ml syringes of blood make up half a UK pint?
28.41
How many ounces is 20ml?
That is approximately 0.705 ounce
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M nitric acid solution?
To neutralize the nitric acid, you need a 1:1 mole ratio of sodium hydroxide to nitric acid. First, calculate the moles of nitric acid in the solution using the formula Molarity = moles/volume. Then, use the mole ratio to find the moles of sodium hydroxide needed. Finally, convert this to grams using the molar mass of sodium hydroxide.
How many milliliters in 20 ounce?
20mL is about 0.68 US fluid ounces.
If 20mL of blood is spun in centrifuge how many milliliters of plasma can be extracted?
Usually 40-50% of the blood volume i.e. 8-10ml.
How many Moles of NaOH equals the moles of KHP?
When titrating NaOH with KHP (potassium hydrogen phthalate), the number of moles of NaOH will be equal to the number of moles of KHP at the equivalence point. This is because the reaction is stoichiometric, with one mole of NaOH reacting with one mole of KHP.
How many moles are there in 9.4 g of NaOH?
To find the number of moles in 9.4 g of NaOH, you first need to calculate the molar mass of NaOH (22.99 g/mol for Na, 15.999 g/mol for O, and 1.008 g/mol for H). Add these together to get 39.997 g/mol for NaOH. Next, divide the given mass by the molar mass to get the number of moles: 9.4 g / 39.997 g/mol ≈ 0.235 moles of NaOH.
