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How many ml of 6.0 N NaOH is required to neutralize 30 ml of 4 N HCL?
Wiki User
∙ 13y ago
formula for neutralizatrion is
volume of acid X normality of acid = volume of base X normality of base
so
(0.3)(3) should equal (4)(volume)
which is .225L.
However, Ca(OH)2 contains 2 moles of OH resulting division of total volume needed by 2.
Thus, the answer becomes .1125L or 112.5ml.
Wiki User
∙ 14y ago
Wiki User
∙ 13y ago1 mole of NaOH will neutralize 1 mole of HCl.
How many moles of HCl do you have in 30 ml of 4 N HCl? Well, 1 L * 1 N = 1 mol.
So, 30 ml = 0.03 L. 0.03 L * 4 N = 0.12 mol HCl. That means you will need 0.12 mol NaOH to neutralize your HCl.
Now, how many mL of 6.0 N NaOH will give us 0.12 mol NaOH? 0.12 mol / 6 N = 0.02 L NaOH = 20 mL.
Thus, you will need 20 mL 6.0 N NaOH to neutralize 30 mL of 4 N HCl.
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When just enough acid has been added to neutralize the sodium hydroxide what will the pH be?
When just enough strong acid (e.g. HCl) is used to neutralize a strong base (NaOH), the pH should be neutral (pH = 7.0).
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The answer would be theoretically , 16.4* 6.9/300=0.3772M But one thing this concentration of NaOH is pretty high, and is not practical to make this solution. Concentration 6.9M means that you'll have to dissolve 40*6.9=286gm NaOH in one 1 litre water. Thus more than 4 gm are present in that 16.4 ml, which is very difficult.
Which two compounds are electrolytes?
NaOH and HCl
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in benzoylation of amine, HCl is produced which by adding NaOH, HCl consumed and the raction proceed for production of further benzoylation product.
How many moles of NaCl are formed from the reaction between 1.4 moles of HCl and 2.8 moles NaOH?
1.4 moles - the HCl is the limiting ingredient
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M1V1=M2V2... By plugging in, you get 18.48 mL of NaOH
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10 mL
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1st Get the balanced equation NaOH + HCl -> NaCl + H2O Find the number of moles in HCl; n = cv n = 0.46x0.61 n = 0.2806 moles the number of moles of HCl and NaOH is the same so 0.2806moles will be needed
Formula for NaOH and HCl?
NaOH and HCl
How many ml of 0.43 m naoh will be needed to neutralize 10 ml of stomach acid if stomach acid is 0.1 m hcl?
Balanced equation first.NaOH + HCl -> NaCl + H2OAll one to one so a simple equality will do here.(X ml)(0.43 M NaOH) = (10 ml)(0.1 M HCl)0.43X = 1X = 2.3 milliliters NaOH needed--------------------------------------
What volume of 0.200 m hcl is required to completely neutralize 20.00 0f 0.300 m koh?
30 mL of HCl
Combination of HCl and NaOH?
The product is sodium chloride.The reaction is:NaOH + HCl - NaCl + H2O
What is HCl NaOH H2O is it Salt?
HCl is an acid which reacts with NaOH a base to produce H2O water and a salt - in this case NaCl HCl + NaOH = NaCl + H2O
When just enough acid has been added to neutralize the sodium hydroxide what will the pH be?
When just enough strong acid (e.g. HCl) is used to neutralize a strong base (NaOH), the pH should be neutral (pH = 7.0).
What do you call a process where an acid and a base neutralize one another?
The process where an acid and a base neutralize each other are called neutralization reaction. The products of this process are a salt and water. For example:- NaOH + HCl -------> NaCl + H2O
How much caustic soda is required to neutralize a 25ml HCl solution at pH 3?
One step at a time.1/103 = 0.001 M HCl, so.....Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters )0.001 M HCl = X moles HCl/0.025 Liters= 2.5 X 10 - 5 moles HCl========================now, balanced eqiationNaOH + HCl --> NaCl + H2O ( all one to one )( now drive reaction towards mass NaOH )2.5 X 10 - 5 moles HCl (1 moles NaOH/1 mole HCl)(39.998 grams/1 mole NaOH)= 10 -4 grams caustic soda needed==========================
