Molecular mass of NaOH= 40.0 grams
9.40 grams / (40.0 grams) = .235 moles NaOH
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
To calculate the mass of 2.5 moles of sodium hydroxide (NaOH), you need to know the molar mass of NaOH, which is 40 g/mol. Multiply the number of moles by the molar mass: 2.5 moles x 40 g/mol = 100 grams of sodium hydroxide.
To determine the grams of sodium hydroxide in 0.150 mol, you need to use the molar mass of NaOH, which is 40.00 g/mol (Na = 22.99 g/mol, O = 16.00 g/mol, H = 1.01 g/mol). 0.150 mol NaOH x 40.00 g/mol = 6.00 grams of NaOH.
To find the number of moles in 40 grams of sodium hydroxide, you first need to calculate the molar mass of NaOH. The molar mass of NaOH is about 40 g/mol. Then, you divide the given mass by the molar mass to get the number of moles. So, 40 grams divided by 40 g/mol is equal to 1 mole of NaOH.
0.1 M sodium hydroxide solution contains 0.1 moles of sodium hydroxide per liter of solution. This corresponds to 0.1 moles of NaOH per 40 g (1 mole) of NaOH, resulting in 4 g of NaOH in 1 liter of 0.1 M NaOH solution.
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
To find the number of moles in 30.0 g of NaOH, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40 g/mol (sodium: 23 g/mol + oxygen: 16 g/mol + hydrogen: 1 g/mol). Therefore, 30.0 g of NaOH is equal to 30.0 g / 40 g/mol = 0.75 moles.
To find the number of moles of NaOH in 8 g, first calculate the molar mass of NaOH (sodium hydroxide) which is approximately 40 g/mol (sodium - 23 g/mol, oxygen - 16 g/mol, hydrogen - 1 g/mol). Then, divide the given mass (8 g) by the molar mass to get the number of moles. So, 8 g / 40 g/mol = 0.2 moles of NaOH.
To find the number of moles in 80.0g of NaOH, divide the given mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40.0 g/mol (sodium - 22.99 g/mol, oxygen - 16.00 g/mol, hydrogen - 1.01 g/mol). Therefore, there are 2.00 moles of NaOH in 80.0g.
To find the number of moles in 12.0 g of NaOH, you first need to calculate its molar mass. The molar mass of NaOH (sodium hydroxide) is 39.997 g/mol. Next, you divide the given mass by the molar mass: 12.0 g / 39.997 g/mol ≈ 0.30 moles of NaOH.
To calculate the number of moles of NaOH, we use the formula: moles = molarity x volume (in liters). First, convert 20 mL to liters (0.02 L). Then, use the formula to find: moles = 0.5 mol/L x 0.02 L = 0.01 moles of NaOH present in 20 ml of 0.5M NaOH.
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
To convert grams of NaOH to moles, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). Thus, 20 grams of NaOH is equivalent to 0.5 moles (20 g / 40 g/mol).
2.00 M NaOH = 2 moles NaOH/litermolar mass NaOH = 40 g/mole2 moles/liter x 40 g/mole = 80 g/liter(x L)(80 g/L) = 32.0 gx = 0.4 liters = 400 mls needed
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH