We have 2.1 moles of H3PO4
However , there are three hydrogen atoms. So this makes for 3 x 2.1 = 6.3 moles of hydrogen atoms.
Further, hydrogen exists as the diatomic molecule 'H2'. So a 'free' hydrogen molecules of H2 we have 6.3 / 2 = 3.15 moles(H2)
Actually H3PO4 is a molecular formula referring to the compound we know as Phosphoric acid. It doesn't indicate number of moles of H3PO4. But the number of moles can be found out if the amount in mass or some other measurable quantity(e.g. conc. in solution) is given. The molar mass(mass of 1 mole) of H3PO4 is 98 grams. So if mass is given then it can be converted to grams and dividing by molar mass(i.e 98) we get number of moles. moles of H3PO4 =(mass of H3PO4 in grams)/98. 1 mole of H3PO4 has ->3 moles of H atoms. ->1 mole of P atoms. ->4 moles of O atoms. ( 1 mole=6.0225 *1023 units)
One mole of phosphoric acid (H3PO4) contains three moles of hydrogen atoms. This is because there are three hydrogen atoms in each molecule of phosphoric acid. Each mole of phosphoric acid contributes three moles of hydrogen atoms to the overall chemical formula.
As 1 molecule of H3PO4 contains 3 hydrogen atoms, 4.56x1023 contain 3x(4.56x1023) hydrogen atoms.
Since H3PO4 has 3 ionizable hydrogens, it will have three Ka values. Approximate values areKa1 = 7x10^-3; Ka2 = 6x10^-8 and Ka3 = 4.5x10^-13
The dissociation of 2 protons from trihydrogen phosphate (H3PO4) results in the formation of dihydrogen phosphate (H2PO4-) and a water molecule (H2O). The chemical equation for this process can be written as: H3PO4 ⇌ H2PO4- + H+ + H2O
Actually H3PO4 is a molecular formula referring to the compound we know as Phosphoric acid. It doesn't indicate number of moles of H3PO4. But the number of moles can be found out if the amount in mass or some other measurable quantity(e.g. conc. in solution) is given. The molar mass(mass of 1 mole) of H3PO4 is 98 grams. So if mass is given then it can be converted to grams and dividing by molar mass(i.e 98) we get number of moles. moles of H3PO4 =(mass of H3PO4 in grams)/98. 1 mole of H3PO4 has ->3 moles of H atoms. ->1 mole of P atoms. ->4 moles of O atoms. ( 1 mole=6.0225 *1023 units)
One mole of phosphoric acid (H3PO4) contains three moles of hydrogen atoms. This is because there are three hydrogen atoms in each molecule of phosphoric acid. Each mole of phosphoric acid contributes three moles of hydrogen atoms to the overall chemical formula.
As 1 molecule of H3PO4 contains 3 hydrogen atoms, 4.56x1023 contain 3x(4.56x1023) hydrogen atoms.
The answer is 10 moles.
Since H3PO4 has 3 ionizable hydrogens, it will have three Ka values. Approximate values areKa1 = 7x10^-3; Ka2 = 6x10^-8 and Ka3 = 4.5x10^-13
The dissociation of 2 protons from trihydrogen phosphate (H3PO4) results in the formation of dihydrogen phosphate (H2PO4-) and a water molecule (H2O). The chemical equation for this process can be written as: H3PO4 ⇌ H2PO4- + H+ + H2O
The combustion of butane (C₄H₁₀) can be represented by the balanced equation: 2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O. From this equation, we see that 2 moles of butane produce 8 moles of carbon dioxide. Therefore, if 5.31 moles of C₄H₁₀ are used, the moles of CO₂ produced can be calculated as follows: (5.31 moles C₄H₁₀) × (8 moles CO₂ / 2 moles C₄H₁₀) = 21.24 moles of CO₂.
Specifically, there are 3 hydrogen (H) atoms, 1 phosphorus (P) atom, and 4 oxygen (O) atoms.
moles H = 0.3086 H x 1 mol/1 g = 0.3086 moles Hmoles P = 3.161 g x 1 mol/31 g = 0.101 moles Pmoles O = 6.541 g x 1 mol/16 g = 0.41 moles Odivide all by 0.101 to get 3.0 moles H, 1 mole P and 4 moles OEmpirical formula = H3PO4
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
Probably, thhere are three elements hydrogen, phosphorus and oxygen
The elements in phosphoric acid (H3PO4) are hydrogen (H), phosphorus (P), and oxygen (O).