1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
Just moles against the ratio of hydrogen atoms in compound then against Avogadro's number. Like this 0.09 moles H2SO4 (2 moles H/1 mole H2SO4)(6.022 X 10^23/1 mole H) = 1.1 X 10^23 hydrogen atoms
A mole of sulfuric acid (H2SO4) contains one mole of sulfur (S), two moles of hydrogen (H), and four moles of oxygen (O).
When H2SO4 dissociates in water, it forms two steps of dissociation. First, it breaks into H+ and HSO4-. Then, HSO4- further dissociates into H+ and SO4^2-. This results in the formation of 2 moles of H+ ions and 1 mole of SO4^2- ion for every mole of H2SO4 dissociated.
H2SO4 H= 1X2 = 2 S=32X1=32 O=16X4=64 TOTAL: 98 98x3= 294 GRAMS =))
To calculate the mass of H2SO4 required, first calculate the number of moles needed using the formula: moles = molarity x volume (in liters). Then, multiply the moles by the molar mass of H2SO4 (98.08 g/mol) to find the mass. moles = 0.15 mol/L x 0.75 L = 0.1125 mol mass = 0.1125 mol x 98.08 g/mol ≈ 11.04 g of H2SO4.
Just moles against the ratio of hydrogen atoms in compound then against Avogadro's number. Like this 0.09 moles H2SO4 (2 moles H/1 mole H2SO4)(6.022 X 10^23/1 mole H) = 1.1 X 10^23 hydrogen atoms
A mole of sulfuric acid (H2SO4) contains one mole of sulfur (S), two moles of hydrogen (H), and four moles of oxygen (O).
When H2SO4 dissociates in water, it forms two steps of dissociation. First, it breaks into H+ and HSO4-. Then, HSO4- further dissociates into H+ and SO4^2-. This results in the formation of 2 moles of H+ ions and 1 mole of SO4^2- ion for every mole of H2SO4 dissociated.
H2SO4 H= 1X2 = 2 S=32X1=32 O=16X4=64 TOTAL: 98 98x3= 294 GRAMS =))
To calculate the mass of H2SO4 required, first calculate the number of moles needed using the formula: moles = molarity x volume (in liters). Then, multiply the moles by the molar mass of H2SO4 (98.08 g/mol) to find the mass. moles = 0.15 mol/L x 0.75 L = 0.1125 mol mass = 0.1125 mol x 98.08 g/mol ≈ 11.04 g of H2SO4.
Well, darling, if we're talking about a 1:2 molar ratio between NaOH and H2SO4, then you'd need 2 moles of NaOH to neutralize 1 mole of H2SO4. It's all about those stoichiometry dance moves, honey. Just make sure you're not tripping over your chemical equations!
Since H2SO4 is a diprotic acid, it will require twice the amount of NaOH to neutralize it. Therefore, molarity of NaOH should also be 1 M. 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, to neutralize 1 mole of H2SO4, 2 moles of NaOH are required. To neutralize 1 mole of H2SO4 in 100 ml (0.1 L) of 1 M solution, you will need 0.1 moles of NaOH.
The answer is 10 moles.
4.75 moles H2SO4 (2 mole H/1 mole H2SO4)(6.022 X 1023/1 mole H)(1 mole H atoms/6.022 X 1023) = 9.67 moles of hydrogen atoms ------------------------------------------ As you can see this set up is formal as the two last steps are superfluous when Avogadro's number actually apears over itself as a form of 1.
To completely neutralize 100ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so it will require 2 moles of NaCl to neutralize 1 mole of H2SO4. Therefore, you would need 2 moles of NaCl for every mole of H2SO4. With a 1M solution of H2SO4 in 100ml, you have 0.1 moles of H2SO4. Therefore, you would need 0.2 moles of NaCl. The molar mass of NaCl is approximately 58.44g/mol, so you would need approximately 11.7 grams of NaCl to completely neutralize the 1M H2SO4 solution.
One gram-molecular weight of any substance contains Avogadro's number of molecules. For H2SO4, the gram-molecular weight is 98 g (2 for H, 32 for S, and 4 for O), so 1 gram of H2SO4 contains 1/98 moles of H2SO4 molecules, which is approximately 6.02 x 10^23 molecules.
The oxidation number of hydrogen (H) in H2SO4 is +1.