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How grams of NaOH is required to nuetralize 100 ml of 1 M H2SO4?
Since H2SO4 is a diprotic acid, it will require twice the amount of NaOH to neutralize it. Therefore, molarity of NaOH should also be 1 M. 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, to neutralize 1 mole of H2SO4, 2 moles of NaOH are required. To neutralize 1 mole of H2SO4 in 100 ml (0.1 L) of 1 M solution, you will need 0.1 moles of NaOH.
How many grams of NaCl are required to completely neutrilaze 100ml of 1M of H2SO4?
To completely neutralize 100ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so it will require 2 moles of NaCl to neutralize 1 mole of H2SO4. Therefore, you would need 2 moles of NaCl for every mole of H2SO4. With a 1M solution of H2SO4 in 100ml, you have 0.1 moles of H2SO4. Therefore, you would need 0.2 moles of NaCl. The molar mass of NaCl is approximately 58.44g/mol, so you would need approximately 11.7 grams of NaCl to completely neutralize the 1M H2SO4 solution.
How many grams of NaCl are required to completely neutralize 100ml of 1M of H2SO4?
To completely neutralize 100 ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so you need 2 moles of NaCl for each mole of H2SO4. Therefore, you would need 2 moles of NaCl, which is equal to 117 grams (2 x molar mass of NaCl) to neutralize 100 ml of 1M H2SO4.
What volume (in liters) of a 1.9 M NaOH solution would neutralize 7.2 moles of H2SO4 (diprotic)?
To neutralize 1 mole of diprotic acid (H2SO4), you need 2 moles of NaOH. Therefore, to neutralize 7.2 moles of H2SO4, you would need 14.4 moles of NaOH. Using the formula M = mol/L, where M is the molarity, mol is the amount of solute in moles, and L is the volume in liters, you can calculate the volume of the 1.9 M NaOH solution needed as 7.57 liters.
What mass of limestone in kg would be required to completely neutralize a 15.4 billion-liter lake that is 1.9105 M in H2SO4 and 8.7106 M in HNO3?
To calculate the amount of limestone needed, first determine the moles of H2SO4 and HNO3 in the lake. Then, use the stoichiometry of the neutralization reaction between limestone (CaCO3) and the acids to calculate the moles of limestone required to neutralize the acids. Finally, convert the moles of limestone to kilograms using the molar mass of CaCO3.
How grams of NaOH is required to nuetralize 100 ml of 1 M H2SO4?
Since H2SO4 is a diprotic acid, it will require twice the amount of NaOH to neutralize it. Therefore, molarity of NaOH should also be 1 M. 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, to neutralize 1 mole of H2SO4, 2 moles of NaOH are required. To neutralize 1 mole of H2SO4 in 100 ml (0.1 L) of 1 M solution, you will need 0.1 moles of NaOH.
How many grams of NaCl are required to completely neutrilaze 100ml of 1M of H2SO4?
To completely neutralize 100ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so it will require 2 moles of NaCl to neutralize 1 mole of H2SO4. Therefore, you would need 2 moles of NaCl for every mole of H2SO4. With a 1M solution of H2SO4 in 100ml, you have 0.1 moles of H2SO4. Therefore, you would need 0.2 moles of NaCl. The molar mass of NaCl is approximately 58.44g/mol, so you would need approximately 11.7 grams of NaCl to completely neutralize the 1M H2SO4 solution.
How many grams of NaCl are required to completely neutralize 100ml of 1M of H2SO4?
To completely neutralize 100 ml of 1M H2SO4, you would need an equal number of moles of NaCl. H2SO4 is a diprotic acid, so you need 2 moles of NaCl for each mole of H2SO4. Therefore, you would need 2 moles of NaCl, which is equal to 117 grams (2 x molar mass of NaCl) to neutralize 100 ml of 1M H2SO4.
What volume (in liters) of a 1.9 M NaOH solution would neutralize 7.2 moles of H2SO4 (diprotic)?
To neutralize 1 mole of diprotic acid (H2SO4), you need 2 moles of NaOH. Therefore, to neutralize 7.2 moles of H2SO4, you would need 14.4 moles of NaOH. Using the formula M = mol/L, where M is the molarity, mol is the amount of solute in moles, and L is the volume in liters, you can calculate the volume of the 1.9 M NaOH solution needed as 7.57 liters.
What mass of limestone in kg would be required to completely neutralize a 15.4 billion-liter lake that is 1.9105 M in H2SO4 and 8.7106 M in HNO3?
To calculate the amount of limestone needed, first determine the moles of H2SO4 and HNO3 in the lake. Then, use the stoichiometry of the neutralization reaction between limestone (CaCO3) and the acids to calculate the moles of limestone required to neutralize the acids. Finally, convert the moles of limestone to kilograms using the molar mass of CaCO3.
What is the number of moles os H2SO4 in 100mL of 12M H2SO4 solution?
To find the number of moles of H2SO4 in 100 mL of 12M H2SO4 solution, you first need to convert the volume to liters, which is 0.1 L. Then, you multiply the volume in liters by the molarity to get the moles of H2SO4. So, 0.1 L * 12 mol/L = 1.2 moles of H2SO4.
What mass of h2so4 would required to prepare 750 ml of a 0.15m h2so4 solution?
To calculate the mass of H2SO4 required, first calculate the number of moles needed using the formula: moles = molarity x volume (in liters). Then, multiply the moles by the molar mass of H2SO4 (98.08 g/mol) to find the mass. moles = 0.15 mol/L x 0.75 L = 0.1125 mol mass = 0.1125 mol x 98.08 g/mol ≈ 11.04 g of H2SO4.
How many hydrogen atoms are in 0.09 moles of H2SO4 Please explain as well?
Just moles against the ratio of hydrogen atoms in compound then against Avogadro's number. Like this 0.09 moles H2SO4 (2 moles H/1 mole H2SO4)(6.022 X 10^23/1 mole H) = 1.1 X 10^23 hydrogen atoms
What Is the mass in grams of 6.25 moles of h2so4?
To calculate the mass of a substance in grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of H2SO4 (sulfuric acid) is approximately 98.08 g/mol. Therefore, the mass of 6.25 moles of H2SO4 would be 6.25 moles x 98.08 g/mol = 613 grams.
What mass of potassium hydroxide is required to react completely with 2.70 g of sulfuric acid to produce potassium sulfate and water?
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
How many NaOH required to neutralize complitly4.9 gms of H2SO4?
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
How much 66 baume sulfuric acid is required to neutralize 350lbs of sodium hydroxide?
66 Baume Sulfuric Acid is contains 93.2% H2SO4 by weight in water. It requires 1 lbmol of H2SO4 to neutralize 2 lbmol of NaOH. Assuming that 350 lbs of NaOH is pure, there are 8.75 lbmol of NaOH. (Divide 350lb by 40 lb/lbmol, the MW of NaOH.) It takes 4.375 lbmol of H2SO4 to neutralize the 350 lb of NaOH because there are 2 lbmol of H per lbmol of H2SO4 and one lbmol of OH per lbmol of NaOH. 4.375 lbmol is equivalent to 428.75 lb of H2SO4. (Multiply by 98 lb/lbmol, the MW of H2SO4.) Then divide by 93.2% or 0.932 to get the quanty of 66 Baume containing 428.75 lb of H2SO4. 460 lb of 66 Baume. The density of 66 Baume is 1.8354 g/cm3 which is equivalent to 15.32 lb/gallon. (Mulitply by 8.345.) Finally, it requires 30 gallons of 66 baume to neutralize 350 lbs of NaOH. (Divide 460 by 15.32.)
