0
What is the number of moles os H2SO4 in 100mL of 12M H2SO4 solution?
Wiki User
∙ 11y ago
The answer is 1,2 mol.
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4?
The answer is 0,526 mL.
How many moles of sulfuric acid are in 500 mL of 0.324 M sulfuric acid solution?
Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
What is the difference between 6 M H2SO4 and 0.1 M H2SO4?
The first solution is more concentrated because it contains 6 moles of H2SO4 per one liter of solution. The second solution is less concentrated because it contains 0.1 moles of H2SO4 in one liter. In equal amounts of each example, the first would have more H2SO4.
Moles of H2SO4 in 20 ml of 4M solution?
The answer is 0,08 mol.
If 25.0 ml of 1.48m h2so4 can be neutralized with 27.29 ml of koh what is the molarity of the koh?
25 milliliters of the solution has . 037 moles of H2SO4. The neutralization reaction is H2SO4 + 2 KOH yields 2 H2O + K2SO4. So, . 074 moles of KOH are required. This equals 2. 71 mL of solution.
What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4?
The answer is 0,526 mL.
How many moles of sulfuric acid are in 500 mL of 0.324 M sulfuric acid solution?
Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
What is the N in 2N h2so4?
N stands for molality and it indicates the number of moles of a substance in a unit mass of the solution.
Moles of H2SO4 in 20 ml of 4M solution?
The answer is 0,08 mol.
What is the difference between 6 M H2SO4 and 0.1 M H2SO4?
The first solution is more concentrated because it contains 6 moles of H2SO4 per one liter of solution. The second solution is less concentrated because it contains 0.1 moles of H2SO4 in one liter. In equal amounts of each example, the first would have more H2SO4.
How many liters of a 4 molar solution of H2SO4 is needed to provide 100 g of H2SO4?
Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity.
How many moles of H2SO4 are in 20 ml of 4 M solution?
The answer is o,1 mol.
If 25.0 ml of 1.48m h2so4 can be neutralized with 27.29 ml of koh what is the molarity of the koh?
25 milliliters of the solution has . 037 moles of H2SO4. The neutralization reaction is H2SO4 + 2 KOH yields 2 H2O + K2SO4. So, . 074 moles of KOH are required. This equals 2. 71 mL of solution.
How many moles of which reactant are in excess when 359.0 mL of 0.259 M sulfuric acid reacts with 0.510 L of 0.191 M sodium hydroxide to form water and aqueous sodium sulfate?
Balanced equation first. 2NaOH + H2SO4 -> Na2SO4 +2H2O Molarity = moles of solute/Liters of solution 0.259 M H2SO4 = moles H2SO4/0.359 liters = 0.09298 moles H2SO4 0.191 M NaOH = moles of NaOH/0.510 liters = 0.09741 moles NaOH ( Let us find limiting reactant ) 0.09298 moles H2SO4 (1 mole H2SO4/2 mole NaOH) = 0.04649 moles H2SO4-- Sulfuric acid limits and, 0.04648 moles of sodium hydroxide are in excess.
What is the mass in moles of 16.4 mL H2SO4 solution d equals 1.727 gmL 80.0 percent H2SO4 by mass?
The answer is 20,5 g or 0,209 mol.
A 3.0 L solution contains 73.5 g of H2SO4 Calculate the molar concentration of the solution?
A)1. H2SO4 is the solute2. Water is the solvent3. Molarity = moles of solute / liter of solution = n / V(Note the case of the letters is important in science. N stands for Normal in chemistry a type of concentration, n stands for number of moles)Rearrange the formula to find nn = M x VHere are the known values,M = 3.5Mn = x molV = 1.00LPlug it in and solve for n (the number of moles of H2SO4 in the solution)n = 3.5M x 1.00 L = 3.50 mol of H2SO4Molecular mass of H2SO4 is 1g/mole H x 2 + 32.1g/mol S + 16g/mol O x 4 = 98.1g/mol H2SO4mass = number of mole x relative molecular massmass = n x 98.1g/molmass = 98.1g/mol H2SO4 x 3.50mol H2SO4= 343g H2SO4
How many moles are in 3.4 10 to the power of 23 molecules of H2SO4?
Simply divide by the number that signifies moles of any thing; Avogadro's number. 3.4 X 10^23/6.022 X 10^23 = 0.56 moles of H2SO4
