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Moles of H2SO4 in 20 ml of 4M solution?
To find the moles of H2SO4 in a 20 ml of 4M solution, use the formula: Moles = Molarity x Volume (in liters). First, convert 20 ml to liters (20 ml = 0.02 L). Then, multiply the molarity (4 mol/L) by the volume (0.02 L) to find the moles of H2SO4, which is 0.08 moles.
What is the molarity of 10 moles of salt dissolved in 20 liters of water?
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
How many moles are present in a sample of H2SO4 with a mass of 9.8g?
To find the number of moles in the sample of H2SO4, we need to divide the given mass by its molar mass. The molar mass of sulfuric acid (H2SO4) is 98.08 g/mol. Therefore, 9.8g / 98.08 g/mol = 0.1 moles of H2SO4.
How many moles of Na2CO3 are there in 10.0 L of 2.0 M soluton?
Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------
How many moles are dissolved in 200 ml of 0.100 M HCl?
There are 0.020 moles of HCl dissolved in 200 ml of 0.100 M HCl solution. This is calculated by multiplying the volume of the solution by the molarity of the solute.
Moles of H2SO4 in 20 ml of 4M solution?
To find the moles of H2SO4 in a 20 ml of 4M solution, use the formula: Moles = Molarity x Volume (in liters). First, convert 20 ml to liters (20 ml = 0.02 L). Then, multiply the molarity (4 mol/L) by the volume (0.02 L) to find the moles of H2SO4, which is 0.08 moles.
What is the molarity of 10 moles of salt dissolved in 20 liters of water?
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
How many moles are present in a sample of H2SO4 with a mass of 9.8g?
To find the number of moles in the sample of H2SO4, we need to divide the given mass by its molar mass. The molar mass of sulfuric acid (H2SO4) is 98.08 g/mol. Therefore, 9.8g / 98.08 g/mol = 0.1 moles of H2SO4.
How many moles of Na2CO3 are there in 10.0 L of 2.0 M soluton?
Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------
How many moles are dissolved in 200 ml of 0.100 M HCl?
There are 0.020 moles of HCl dissolved in 200 ml of 0.100 M HCl solution. This is calculated by multiplying the volume of the solution by the molarity of the solute.
How many moles of strontium chloride are includes in 20 ml of 0.2 moles strontium chloride?
To find the number of moles of strontium chloride in 20 mL of a 0.2 M solution, you can use the formula: moles = concentration (M) × volume (L). First, convert 20 mL to liters, which is 0.020 L. Then, calculate the moles: 0.2 moles/L × 0.020 L = 0.004 moles of strontium chloride.
How many moles of He are 1.201025 atoms He?
20 moles
How many grams of LiCl would you use to make 20 ml of a 4M solution?
To make a 4M solution in 20 ml, you would need 0.32 grams of LiCl. This can be calculated using the formula: moles = molarity x volume (in L), then converting moles to grams using the molar mass of LiCl.
How many oxygen atom are in 5 molecules oh H2so4?
Five molecules of H2SO4 contains 20 atoms of Oxygen
How many moles of Al would be produced from 20 moles if Al2O3?
To determine how many moles of aluminum (Al) are produced from 20 moles of aluminum oxide (Al2O3), we need to use the balanced chemical equation for the reduction of Al2O3. The equation is: 2 Al2O3 → 4 Al + 3 O2. From this, we see that 2 moles of Al2O3 produce 4 moles of Al. Therefore, from 20 moles of Al2O3, we can calculate that 20 moles of Al2O3 would produce 40 moles of Al.
How many grams of barium chloride are needed to make 20 mL of a 2m solution?
To prepare a 2 m solution of barium chloride (BaCl₂), you need to know the molarity (moles per liter) and the molecular weight of BaCl₂, which is approximately 208.23 g/mol. For a 2 m solution, you need 2 moles per kilogram of solvent. Since 20 mL is 0.02 kg, you would need 0.04 moles of BaCl₂ (2 moles/kg × 0.02 kg). Multiplying 0.04 moles by the molar mass (208.23 g/mol) gives approximately 8.33 grams of barium chloride.
How many moles in 20g of magnesium nitrate?
There are 0.13 moles in 20 grams of magnesium nitrate.
