Molarity = moles of solute/Liters of solution
Molarity = 10 moles salt/20 Liters solution
= 0.50 M salt solution
----------------------------
The molarity is calculated by dividing the moles of solute by the liters of solution. In this case, with 2 moles of compound dissolved in 4 liters of water, the molarity would be 0.5 M (2 moles / 4 L = 0.5 M).
To find the molarity, first calculate the number of moles of LiCl in 230 mL of water. Then, divide the moles of LiCl by the volume of water in liters (230 mL = 0.23 L) to get the molarity. In this case, 2.60 moles of LiCl in 0.23 L of water would result in a molarity of 11.30 mol/L.
The molarity of the solution is 3 M. This is calculated by dividing the moles of solute by the volume of solution in liters. In this case, 6 moles divided by 2 liters equals a molarity of 3 M.
6mol/2L
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
The molarity is calculated by dividing the moles of solute by the liters of solution. In this case, with 2 moles of compound dissolved in 4 liters of water, the molarity would be 0.5 M (2 moles / 4 L = 0.5 M).
To find the molarity, first calculate the number of moles of LiCl in 230 mL of water. Then, divide the moles of LiCl by the volume of water in liters (230 mL = 0.23 L) to get the molarity. In this case, 2.60 moles of LiCl in 0.23 L of water would result in a molarity of 11.30 mol/L.
The molarity of the solution is 3 M. This is calculated by dividing the moles of solute by the volume of solution in liters. In this case, 6 moles divided by 2 liters equals a molarity of 3 M.
To determine the molarity, you need to know the volume of water the 3 moles of FeBr3 are dissolved in. With this information, you can use the formula: Molarity (M) = Moles of solute / Liters of solution. Therefore, if you dissolve 3 moles of FeBr3 in 1 liter of water, the molarity would be 3 M.
6mol/2L
The molarity can be calculated using the formula: moles of solute divided by liters of solution. In this case, the moles of sucrose is 25, and the liters of solution is 50. This gives a molarity of 0.5 M.
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
The molarity of the solution can be calculated by dividing the moles of solute by the volume of solution in liters. In this case, 2 moles of NaOH in 1620 mL (1.62 L) of water gives a molarity of approximately 1.23 M.
Molarity = moles of solute / liters of solution. First, calculate the moles of NaOH using its molar mass. Then, divide the moles by the final volume in liters (3.00 L) to find the molarity.
To find the molarity, first calculate the number of moles of BaCl2 by dividing the mass by its molar mass (Ba: 137.33 g/mol, Cl: 35.45 g/mol). Then, divide the number of moles by the volume of water in liters to get the molarity. In this case, the molarity of 416.48 g of BaCl2 dissolved in 2 L of water is approximately 3.02 M.
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------