1620 ml = 1.62 Liters
Molarity = moles of solute/Liters of solution
Molarity = 2 moles NaOH/1.62 Liters
= 1 M NaOH solution
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The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution is 3 moles / 5 L = 0.6 M.
6mol/2L
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution is 3 moles / 5 L = 0.6 M.
The molarity can be calculated using the formula: moles of solute divided by liters of solution. In this case, the moles of sucrose is 25, and the liters of solution is 50. This gives a molarity of 0.5 M.
6mol/2L
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
To determine the molarity, you need to know the volume of water the 3 moles of FeBr3 are dissolved in. With this information, you can use the formula: Molarity (M) = Moles of solute / Liters of solution. Therefore, if you dissolve 3 moles of FeBr3 in 1 liter of water, the molarity would be 3 M.
This molarity is 3 M.
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
molarity = moles/litre [solution] = 12 mol/6 L [solution] = 2 mol/L = 2 M
6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------
The molarity is 6 mol/l.