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What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
What is the molarity of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.
What is the molarity of a solution made by dissolving 23.4g of sodium sulphate in enough water to make up a 125ml solution?
To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.
What is molarity of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
To find the molarity, we first need to convert the mass of water to volume using the density of water. Given the density of water is approximately 1000 g/L, 6 kg of water is equivalent to 6000 g or 6 L. Next, calculate the molarity using the formula Molarity (M) = moles of solute / liters of solution. In this case, 2 moles of NaOH in 6 L of water gives a molarity of 0.33 M.
How 0.1M NaOH form?
0.1 M NaOH is prepared by dissolving sodium hydroxide (NaOH) pellets or flakes in water to make a 0.1 molar solution. This means there are 0.1 moles of NaOH dissolved in 1 liter of water. The molarity of the solution is calculated using the formula: Molarity = moles of solute / liters of solution.
What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
What is the molarity of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.
What is the molarity of a solution made by dissolving 23.4g of sodium sulphate in enough water to make up a 125ml solution?
To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.
What is the molatity of a solution made by dissolving 6 moles of NaOH in 3 kg of water?
Molarity is defined as the number of moles of solute per liter of solution. To find the molarity of the NaOH solution, we first need to determine the total volume of the solution. Since the density of water is approximately 1 kg/L, 3 kg of water is roughly 3 L. Therefore, the molarity of the solution is 6 moles of NaOH divided by 3 L of solution, which equals 2 M (moles per liter).
What is the molarity of a solution of 3 moles of FeBr3 in 12 L water?
To find the molarity of a solution, you can use the formula: Molarity (M) = moles of solute / liters of solution. In this case, there are 3 moles of FeBr3 in 12 liters of water. Thus, the molarity is 3 moles / 12 L = 0.25 M. Therefore, the molarity of the FeBr3 solution is 0.25 M.
What is molarity of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
To find the molarity, we first need to convert the mass of water to volume using the density of water. Given the density of water is approximately 1000 g/L, 6 kg of water is equivalent to 6000 g or 6 L. Next, calculate the molarity using the formula Molarity (M) = moles of solute / liters of solution. In this case, 2 moles of NaOH in 6 L of water gives a molarity of 0.33 M.
How 0.1M NaOH form?
0.1 M NaOH is prepared by dissolving sodium hydroxide (NaOH) pellets or flakes in water to make a 0.1 molar solution. This means there are 0.1 moles of NaOH dissolved in 1 liter of water. The molarity of the solution is calculated using the formula: Molarity = moles of solute / liters of solution.
What is the molarity of a solution with 2 moles of NaOH in 1620ml of water?
The molarity of the solution can be calculated by dividing the moles of solute by the volume of solution in liters. In this case, 2 moles of NaOH in 1620 mL (1.62 L) of water gives a molarity of approximately 1.23 M.
What is the molarity of 10 moles of salt dissolved in 20 liters of water?
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
What will be the molarity for a solution prepared by dissolving 50 grams of KOH in 700ml of water?
Molarity= Number of moles of solute/Liters of solution 50 grams KOH 700 ML to .7 Liters of h2o Molar Mass of KOH= 56 50 divided by 56 = .89 moles Molarity= .89 mol/.7 L = 1.27 MOLARITY
What is the molarity of a solution of 3 moles of FeBr3 in 5 L water?
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution is 3 moles / 5 L = 0.6 M.
What is the molarity of a solution prepared by dissolving 2.41 g of potassium iodide KI in 100 mL of water?
Find moles potassium iodide first.2.41 grams KI (1 mole KI/166 grams) = 0.01452 moles KIMolarity = moles of solute/Liters of solution ( 100 ml = 0.1 Liters )Molarity = 0.01452 moles KI/0.1 Liters= 0.145 M KI solution================
