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Q: What is molarity of a solution made by dissolving 2 moles of NaOH in 6 kg of water?

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The molarity is 0,2.

The molarity is 2 (or 80 g/L).

By dissolving the same number of moles of each substance in the same volume of water

since molarity = (number of moles) / (volume of solution), the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water will be 5.11 moles.

what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?

Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl

1.99 M

Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------

Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========

Get moles sodium sulfate first.15.5 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.1091 moles Na2SO4Now,Molarity = moles of solute/ Liters of solution ( 35 ml = 0.035 Liters )Molarity = 0.1091 moles Na2SO4/0.035 Liters= 3.1 M Na2SO4 solution==================

1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============

6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------

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