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What is the molatity of a solution made by dissolving 6 moles of NaOH in 3 kg of water?
Molarity is defined as the number of moles of solute per liter of solution. To find the molarity of the NaOH solution, we first need to determine the total volume of the solution. Since the density of water is approximately 1 kg/L, 3 kg of water is roughly 3 L. Therefore, the molarity of the solution is 6 moles of NaOH divided by 3 L of solution, which equals 2 M (moles per liter).
What else can I help you with?
What is the molality of a solution by dissolving 2 moles of NaOH in 10kg of water?
10kg of water contains 10l of water. So morality is 0.2mildm-3.
How would one make 2 M solution of compound?
By dissolving 2 moles of the compound in 1 L of water
How would one make 2 M solution of a compound?
By dissolving 2 moles of the compound in 1 L of water
What is the molality of a solution made by dissolving 6 moles of Noah in 3 kg of water?
To calculate the molality of the solution, use the formula: molality (m) = moles of solute / mass of solvent in kg. Here, there are 6 moles of solute (Noah) and 3 kg of water. Thus, the molality is 6 moles / 3 kg = 2 m. Therefore, the molality of the solution is 2 m.
What is the molality of a solution made by dissolving 2 miles of NaOH in 6 kg of water?
To calculate the molality of a solution, use the formula: molality (m) = moles of solute / mass of solvent in kilograms. Here, you have 2 moles of NaOH and 6 kg of water. Therefore, the molality is 2 moles / 6 kg = 0.33 mol/kg. Thus, the molality of the NaOH solution is 0.33 m.
How would one make M solution of a compound?
By dissolving 2 moles of the compound in 1 L of water
What is the molality of a solution by dissolving 2 moles of NaOH in 10kg of water?
10kg of water contains 10l of water. So morality is 0.2mildm-3.
How would one make 2 M solution of a compound?
By dissolving 2 moles of the compound in 1 L of water
What is the molality of a solution made by a dissolving 2 moles of naoh in 6 kg of water?
0.33 mol/kg (apex)
How would one make 2 M solution of compound?
By dissolving 2 moles of the compound in 1 L of water
What is the molality of a solution made by dissolving 2 moles of NaOH in 10Kg of water?
Molality =moles of solute/kilograms of solvent Moles of solute =2
What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, with 2 moles of NaOH dissolved in 10 kg of water, the molality would be 0.2 mol/kg.
How 0.1M NaOH form?
0.1 M NaOH is prepared by dissolving sodium hydroxide (NaOH) pellets or flakes in water to make a 0.1 molar solution. This means there are 0.1 moles of NaOH dissolved in 1 liter of water. The molarity of the solution is calculated using the formula: Molarity = moles of solute / liters of solution.
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
0.2
What is the molality of a solution made by dissolving 2 miles of NaOH in 6 kg of water?
To calculate the molality of a solution, use the formula: molality (m) = moles of solute / mass of solvent in kilograms. Here, you have 2 moles of NaOH and 6 kg of water. Therefore, the molality is 2 moles / 6 kg = 0.33 mol/kg. Thus, the molality of the NaOH solution is 0.33 m.
What is the molarity of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.
