The molality is 0,2.
Molality =moles of solute/kilograms of solvent Moles of solute =2
0.2
0.33 mol/kg (apex)
0.33 mol/kg
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
To calculate the molality of a solution, use the formula: molality (m) = moles of solute / mass of solvent in kilograms. Here, you have 2 moles of NaOH and 6 kg of water. Therefore, the molality is 2 moles / 6 kg = 0.33 mol/kg. Thus, the molality of the NaOH solution is 0.33 m.
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
0.33 mol/kg (apex)
Molality =moles of solute/kilograms of solvent Moles of solute =2
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
0.2
0.33 mol/kg (apex)
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.
0.33 mol/kg
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality would be 2 mol / 6 kg = 0.33 mol/kg.
10kg of water contains 10l of water. So morality is 0.2mildm-3.