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What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a substance made by dissolving 2 moles of NaOH in 10 kg of water?
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.
What is the molality of a solution by dissolving 2 moles of NaOH in 10kg of water?
10kg of water contains 10l of water. So morality is 0.2mildm-3.
What is the molality of a solution made by a dissolving 2 moles of naoh in 6 kg of water Apex?
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} ). In this case, with 2 moles of NaOH dissolved in 6 kg of water, the molality is ( m = \frac{2 , \text{moles}}{6 , \text{kg}} = \frac{1}{3} , \text{mol/kg} ). Therefore, the molality of the solution is approximately 0.33 mol/kg.
What is the molarity of a solution made by dissolving 6 moles of naoh in 3 kg?
2 mol/kg
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, with 2 moles of NaOH dissolved in 10 kg of water, the molality would be 0.2 mol/kg.
What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a solution made by a dissolving 2 moles of naoh in 6 kg of water?
0.33 mol/kg (apex)
What is the molality of a solution made by dissolving 2 moles of NaOH in 10Kg of water?
Molality =moles of solute/kilograms of solvent Moles of solute =2
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
0.2
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
0.33 mol/kg (apex)
What is the molality of a substance made by dissolving 2 moles of NaOH in 10 kg of water?
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.
What is the molality of a solution made by dissolving two moles of NaOH in 6 kg of water?
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
What is the molality of a solution made by dissolving 2 moles of NaOH in 6kg of water?
0.33 mol/kg
What is the molality of a solution made by dissolving 2 mole of NaOH in 6kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality would be 2 mol / 6 kg = 0.33 mol/kg.
What is the molality of a solution by dissolving 2 moles of NaOH in 10kg of water?
10kg of water contains 10l of water. So morality is 0.2mildm-3.
What is the molarity of a solution made by dissolving 6 moles of naoh in 3 kg?
2 mol/kg
