This molarity is 3 mol/L.
6mol/2L
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
To find the molarity, first calculate the moles of Sodium Chloride using its molar mass. Assuming 58.44 g/mol for NaCl, 2.3 grams is 0.039 moles. Then, divide this by the volume of solution in liters (25 mL = 0.025 L) to get a molarity of 1.56 M.
This is just easy. MOLARITY OF THIS COMPOUND IS 3MOLDM-3.
The molarity of the solution is calculated by dividing the moles of solute (0.250 mol NaCl) by the liters of solution (2.25 L). Molarity = moles of solute / liters of solution Molarity = 0.250 mol / 2.25 L = 0.111 M
6mol/2L
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
This molarity is 3 M.
To find the molarity, first calculate the moles of NaCl using its molar mass (58.44 g/mol). Then, divide the moles of NaCl by the volume of solution in liters (0.1 L) to get the molarity in moles per liter.
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
To find the molarity, first calculate the moles of Sodium Chloride using its molar mass. Assuming 58.44 g/mol for NaCl, 2.3 grams is 0.039 moles. Then, divide this by the volume of solution in liters (25 mL = 0.025 L) to get a molarity of 1.56 M.
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
The Molarity of the solution is .901