0.5 M
The molarity of a solution is the amount of substance in a given amount of solute. The units are usually given as moles per liter (or dm3). As such, for each liter you have 0.5 moles of substance (2 divided by 4), so it's a 0.5 molar solution.
To find the molarity, first calculate the number of moles of LiCl in 230 mL of water. Then, divide the moles of LiCl by the volume of water in liters (230 mL = 0.23 L) to get the molarity. In this case, 2.60 moles of LiCl in 0.23 L of water would result in a molarity of 11.30 mol/L.
6mol/2L
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
To find the molarity, first calculate the number of moles of BaCl2 by dividing the mass by its molar mass (Ba: 137.33 g/mol, Cl: 35.45 g/mol). Then, divide the number of moles by the volume of water in liters to get the molarity. In this case, the molarity of 416.48 g of BaCl2 dissolved in 2 L of water is approximately 3.02 M.
0.5 M
This is just easy. MOLARITY OF THIS COMPOUND IS 3MOLDM-3.
0.5 M
0.5 M
The molarity of a solution is the amount of substance in a given amount of solute. The units are usually given as moles per liter (or dm3). As such, for each liter you have 0.5 moles of substance (2 divided by 4), so it's a 0.5 molar solution.
In moles of a substance dissolved in 1 L of water.
To determine the molarity, you need to know the volume of water the 3 moles of FeBr3 are dissolved in. With this information, you can use the formula: Molarity (M) = Moles of solute / Liters of solution. Therefore, if you dissolve 3 moles of FeBr3 in 1 liter of water, the molarity would be 3 M.
0.5 M
To find the molarity, first calculate the number of moles of LiCl in 230 mL of water. Then, divide the moles of LiCl by the volume of water in liters (230 mL = 0.23 L) to get the molarity. In this case, 2.60 moles of LiCl in 0.23 L of water would result in a molarity of 11.30 mol/L.
6mol/2L
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
The molarity of the solution is 3 M. This is calculated by dividing the moles of solute by the volume of solution in liters. In this case, 6 moles divided by 2 liters equals a molarity of 3 M.