0.5 M
0.5 M
0.5 M
Need to know the mass of BaCl2 in order to calculate molarity.
Yes, the physical properties of water can change when a compound is dissolved in it. For example, the boiling and freezing points of water can be altered, its density may change, and its ability to conduct electricity may be affected depending on the compound dissolved.
Samarium hydroxide (Sr(OH)2) is an ionic compound that dissolves in water to produce Sr2+ and OH- ions. These ions can conduct electricity in solution, making Sr(OH)2 a conductive compound when dissolved in water.
0.5 M
0.5 M
0.5 M
The molarity is calculated by dividing the moles of solute by the liters of solution. In this case, with 2 moles of compound dissolved in 4 liters of water, the molarity would be 0.5 M (2 moles / 4 L = 0.5 M).
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
The molarity of a solution is the amount of substance in a given amount of solute. The units are usually given as moles per liter (or dm3). As such, for each liter you have 0.5 moles of substance (2 divided by 4), so it's a 0.5 molar solution.
The molarity can be calculated by dividing the number of moles of solute by the volume of solution in liters. In this case, the molarity would be 2 M (4 mol NaOH / 2 L water).
To find the molarity, first calculate the number of moles of BaCl2 by dividing the mass by its molar mass (Ba: 137.33 g/mol, Cl: 35.45 g/mol). Then, divide the number of moles by the volume of water in liters to get the molarity. In this case, the molarity of 416.48 g of BaCl2 dissolved in 2 L of water is approximately 3.02 M.
Need to know the mass of BaCl2 in order to calculate molarity.
6mol/2L
The molarity of the solution is 3 M. This is calculated by dividing the moles of solute by the volume of solution in liters. In this case, 6 moles divided by 2 liters equals a molarity of 3 M.
To find the molarity, we first need to calculate the number of moles of NaOH. The molar mass of NaOH is 40 g/mol (sodium=23g/mol, oxygen=16g/mol, hydrogen=1g/mol). Thus, 80g NaOH is 2 moles (80g / 40g/mol). Given 1L of solution, the molarity is 2 moles / 1 L = 2 M.