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How many grams of LiCl would you use to make 20 ml of a 4M solution?
To make a 4M solution in 20 ml, you would need 0.32 grams of LiCl. This can be calculated using the formula: moles = molarity x volume (in L), then converting moles to grams using the molar mass of LiCl.
What is the pH of a solution with a H3O of 2 x 10-4M?
The pH of the solution can be calculated using the formula: pH = -log[H3O+]. Substituting the given value of [H3O+] = 2 x 10^-4M into the formula, pH = -log(2 x 10^-4) = 3.7. Therefore, the pH of the solution is 3.7.
What is normality of sulfuric acid when molarity is 4m?
The normality of sulfuric acid is 8N when the molarity is 4M because sulfuric acid is a diprotic acid, meaning it can donate two moles of protons per molecule. Since normality is the equivalent concentration of a compound, it is double the molarity for a diprotic acid like sulfuric acid.
You want 1 liter of 0.1 M NaCl and you have 4 M stock solution How much of the 4 M solution and how much dH2O will you measure out for this dilution?
To make 1 liter of 0.1 M NaCl solution, you will need 25 ml of the 4 M NaCl stock solution and 975 ml of water. This will give you the desired concentration of 0.1 M NaCl in a total volume of 1 liter.
What is the pH of a 1.0x10-4m hcl solution?
- log(0.00450 M HCl)= 2.3 pH=======
How many grams of LiCl would you use to make 20 ml of a 4M solution?
To make a 4M solution in 20 ml, you would need 0.32 grams of LiCl. This can be calculated using the formula: moles = molarity x volume (in L), then converting moles to grams using the molar mass of LiCl.
How many litters of 4M solution can be made using 100 grams of lithium bromide?
To determine how many liters of a 4M lithium bromide (LiBr) solution can be made from 100 grams of LiBr, we first need to calculate the number of moles in 100 grams. The molar mass of lithium bromide is approximately 86.84 g/mol, so 100 grams corresponds to about 1.15 moles. A 4M solution contains 4 moles of solute per liter, thus 1.15 moles can produce approximately 0.29 liters (1.15 moles ÷ 4 moles/L). Therefore, 100 grams of lithium bromide can make about 0.29 liters of a 4M solution.
How do you solve 4m-4 equals 4m?
It has no solution since subtracting 4m from both sides leads to -4 = 0 which is not true.
When 80g of sodium hydroxide are dissolved in water to make 0.500 of a solution what is the molarity?
The molarity can be calculated by first converting grams of sodium hydroxide to moles, then dividing by the volume of the solution in liters. In this case, the molar mass of NaOH is 40 g/mol. So, 80g is 2 moles. With a volume of 0.5 L, the molarity is 2 moles / 0.500 L = 4 M.
How do you factor Mn - 4m - 5n plus 20?
mn - 4m - 5n + 20 = (mn - 5n) - (4m - 20) = n(m - 5) - 4(m - 5) = (m -5)(n - 4)
How do you solve this 4m plus 15 equals 8m-5?
4m+15=8m-5 or,4m=20 or,m=5
how to solve this 4m-12i need show the solution?
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What is mn - 4m - 5n 20?
mn - 4m - 5n + 20 = m(n - 4) - 5(n - 4) = (n - 4)(m - 5)
What is 3m - 10 2 (4m - 5)?
To simplify the expression (3m - 10 \cdot 2(4m - 5)), first calculate (10 \cdot 2 = 20). Then, distribute (20) across (4m - 5): (20(4m) - 20(5) = 80m - 100). Now, combine this with (3m): (3m - (80m - 100) = 3m - 80m + 100 = -77m + 100). Thus, the simplified expression is (-77m + 100).
What is the molarity of a solution containing .325 moles of solute in 250 ml of solution?
Given the eqaution c=n/v, where:c = concentrationn = number of molesv = volumeso, n=cv, that is: n = .25 X .4= 0.1 mol
What is the perimeter of quadrilateral of 20m and 4m?
Perimeter = 20+20+4+4 = 48m
What is the solution for m given the equation 4m - 29 equals -105?
m = -19
