- log(0.00450 M HCl)
= 2.3 pH
=======
The pH of a 6M HCl solution is 0.
The pH of a solution containing 6M HCl is 0.
The pH of a 0.0001M aqueous solution of HCl is 4. The pH of a solution is calculated using the formula pH = -log[H+], where [H+] is the concentration of hydrogen ions in the solution. Since HCl is a strong acid that dissociates completely in water, the concentration of H+ ions in a 0.0001M solution of HCl is also 0.0001M.
The pH of a 42m HCl solution would be approximately -log(42) = -1.62. This solution is strongly acidic.
The pH of a 0.010 M HCl solution is approximately 2. This is because HCl is a strong acid that completely dissociates in water to form H+ ions, resulting in an acidic solution.
The pH of a 6M HCl solution is 0.
The pH of a solution containing 6M HCl is 0.
The pH of a 0.0001M aqueous solution of HCl is 4. The pH of a solution is calculated using the formula pH = -log[H+], where [H+] is the concentration of hydrogen ions in the solution. Since HCl is a strong acid that dissociates completely in water, the concentration of H+ ions in a 0.0001M solution of HCl is also 0.0001M.
The pH of a 42m HCl solution would be approximately -log(42) = -1.62. This solution is strongly acidic.
The pH of a 0.280 M HCl solution is approximately 0.55. This is because HCl is a strong acid that dissociates completely in solution to produce H+ ions, leading to a low pH value.
its PH is 3
The pH of a 0.010 M HCl solution is approximately 2. This is because HCl is a strong acid that completely dissociates in water to form H+ ions, resulting in an acidic solution.
0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990
The pH of a 0.140 M HCl solution is approximately 0.85. This is because HCl is a strong acid that completely dissociates in water to give H+ ions, resulting in a low pH.
In solution with a pH of 1 [H+] is 0.1M. Since HCl is a strong acid [HCl] will also be 0.1M. So, in 1 liter of solution you will have 0.1 mol of HCl.
To find the pH of a 0.03 N solution of HCl, we first recognize that HCl is a strong acid that dissociates completely in solution. Since the normality (N) of HCl is equal to its molarity (M) for monoprotic acids, a 0.03 N solution corresponds to a concentration of 0.03 M. The pH can be calculated using the formula pH = -log[H⁺], so pH = -log(0.03) ≈ 1.52.
Diluting a 0.01N HCl solution ten times would result in a 0.001N HCl solution. Since HCl is a strong acid that fully dissociates in water, the pH of a 0.001N HCl solution would be around 3 (pH = -log[H+]).