To find the pH of a 0.03 N solution of HCl, we first recognize that HCl is a strong acid that dissociates completely in solution. Since the normality (N) of HCl is equal to its molarity (M) for monoprotic acids, a 0.03 N solution corresponds to a concentration of 0.03 M. The pH can be calculated using the formula pH = -log[H⁺], so pH = -log(0.03) ≈ 1.52.
The pH of a 0.066 M solution of HCl can be calculated using the formula pH = -log[H⁺]. Since HCl is a strong acid, it completely dissociates in solution, so the concentration of H⁺ ions is also 0.066 M. Therefore, pH = -log(0.066) ≈ 1.18.
When hydrochloric acid (HCl) is added to a solution with a pH of 7.45, the acidity of the solution increases. HCl dissociates into hydrogen ions (H⁺) and chloride ions (Cl⁻), which lowers the pH as the concentration of hydrogen ions rises. The solution will become more acidic, moving toward a pH closer to neutral (7) or even below, depending on the amount of HCl added. This change can affect various chemical equilibria and biological processes that are sensitive to pH.
25g HCl 1 mol 36.46g HCl =.686 mol M=.686 mol/1.5 L=.457M pH= -log(.457) pH= .34
A strong acid, such as hydrochloric acid (HCl), has a pH of 1 and completely ionizes in aqueous solution, meaning all molecules dissociate into their constituent ions. This leads to a high concentration of hydrogen ions (H+) in the solution, resulting in the low pH value.
To calculate the pH of a 0.001 mol/dm³ HCl solution, you use the formula pH = -log[H+]. For HCl, since it is a strong acid, it dissociates completely into H⁺ ions. Thus, the concentration of H⁺ ions in a 0.001 mol/dm³ HCl solution is also 0.001 mol/dm³. Taking the negative logarithm of 0.001 gives a pH of 3.
The pH of a 6M HCl solution is 0.
The pH of a solution containing 6M HCl is 0.
- log(0.00450 M HCl)= 2.3 pH=======
The pH of a 0.0001M aqueous solution of HCl is 4. The pH of a solution is calculated using the formula pH = -log[H+], where [H+] is the concentration of hydrogen ions in the solution. Since HCl is a strong acid that dissociates completely in water, the concentration of H+ ions in a 0.0001M solution of HCl is also 0.0001M.
The pH of a 42m HCl solution would be approximately -log(42) = -1.62. This solution is strongly acidic.
The pH of a 0.280 M HCl solution is approximately 0.55. This is because HCl is a strong acid that dissociates completely in solution to produce H+ ions, leading to a low pH value.
its PH is 3
The pH of a 0.010 M HCl solution is approximately 2. This is because HCl is a strong acid that completely dissociates in water to form H+ ions, resulting in an acidic solution.
0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990
The pH of a 0.140 M HCl solution is approximately 0.85. This is because HCl is a strong acid that completely dissociates in water to give H+ ions, resulting in a low pH.
In solution with a pH of 1 [H+] is 0.1M. Since HCl is a strong acid [HCl] will also be 0.1M. So, in 1 liter of solution you will have 0.1 mol of HCl.
Diluting a 0.01N HCl solution ten times would result in a 0.001N HCl solution. Since HCl is a strong acid that fully dissociates in water, the pH of a 0.001N HCl solution would be around 3 (pH = -log[H+]).