The pH of a solution containing 6M HCl is 0.
The pH of a 6M HCl solution is 0.
- log(0.00450 M HCl)= 2.3 pH=======
The pH of a 42m HCl solution would be approximately -log(42) = -1.62. This solution is strongly acidic.
The pH of a 0.0001M aqueous solution of HCl is 4. The pH of a solution is calculated using the formula pH = -log[H+], where [H+] is the concentration of hydrogen ions in the solution. Since HCl is a strong acid that dissociates completely in water, the concentration of H+ ions in a 0.0001M solution of HCl is also 0.0001M.
The pH of a solution containing NaCl is neutral, around 7.
The pH of a 6M HCl solution is 0.
- log(0.00450 M HCl)= 2.3 pH=======
The pH of a 42m HCl solution would be approximately -log(42) = -1.62. This solution is strongly acidic.
The pH of a 0.0001M aqueous solution of HCl is 4. The pH of a solution is calculated using the formula pH = -log[H+], where [H+] is the concentration of hydrogen ions in the solution. Since HCl is a strong acid that dissociates completely in water, the concentration of H+ ions in a 0.0001M solution of HCl is also 0.0001M.
its PH is 3
The pH of a 0.280 M HCl solution is approximately 0.55. This is because HCl is a strong acid that dissociates completely in solution to produce H+ ions, leading to a low pH value.
The pH of a solution containing NaCl is neutral, around 7.
The pH of a solution containing NaH2PO4 is around 4.5.
The pH of a 0.010 M HCl solution is approximately 2. This is because HCl is a strong acid that completely dissociates in water to form H+ ions, resulting in an acidic solution.
0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990
The pH of a 0.140 M HCl solution is approximately 0.85. This is because HCl is a strong acid that completely dissociates in water to give H+ ions, resulting in a low pH.
or at least what's the formula to find the pH?