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How many grams of LiCl are required to make 2.0 L of 0.65 M LiCl solution?

To calculate the number of grams of LiCl required, you need to use the formula: ( \text{grams} = \text{Molarity} \times \text{Volume} \times \text{Molar Mass} ) Given that the molar mass of LiCl is approximately 42.39 g/mol, plug in the values and calculate the grams of LiCl needed.


How many grams of LiCl are required to make 2.0 of 0.65?

To calculate the grams of LiCl needed to make a 2.0 L solution at a concentration of 0.65 M, use the formula: [ \text{grams of solute} = \text{molarity} \times \text{volume (L)} \times \text{molar mass} ] The molar mass of LiCl is approximately 42.39 g/mol. Thus: [ \text{grams of LiCl} = 0.65 , \text{mol/L} \times 2.0 , \text{L} \times 42.39 , \text{g/mol} \approx 55.85 , \text{g} ] Therefore, approximately 55.85 grams of LiCl are required.


How would you make 22.3 percent salt solution?

To make a 22.3% salt solution, you would dissolve 22.3 grams of salt in 100 grams of solution (salt + water). This would result in a solution where 22.3% of the total weight is salt.


How many grams of EDTA do you add to make a 3.7 percent EDTA solution?

To make a 3.7% EDTA solution, you would add 3.7 grams of EDTA to 100 mL of solution.


How is a concentrated solution prepared?

3 Simple Steps!NOTE: Use this answer to make a solution if you need to dissolve a SOLID to make your solution. If instead you are making a solution by diluting another solution, see the Related Questions link for "How do you prepare a solution by diluting another solution?" You must know two things to make a solution: the number of moles of the solute, and the number of liters of solution. That is how the concentration "molarity" (M) is defined: the moles per liter:-- Molarity = moles of solute ÷ liters of solutionor-- Moles of solute = Molarity * liters of solutionNote: The volume is liters of solution, not solvent. That means that the total volume of the solution is what matters, not how much liquid you add.So, to make a solution of a specific concentration, we must figure out how many moles of solute we need. That's easy! Let me illustrate with a few simple examples. Then we'll find how many grams that corresponds to.--- Example 1: How many moles of lithium chloride (LiCl) are needed to make 1 liter of 0.5 M LiCl solution?--- Answer: In 1 liter of 0.5 M LiCl, there are 0.5 moles of LiCl. Therefore the answer is 0.5 moles LiCl.--- Example 2: How many more of sodium hydroxide (NaOH) are needed to make 2 liters of 0.5 M NaOH?--- Answer: In 1 liter of 0.5 M NaOH, there are 0.5 moles. So in 2 liters, there will be 1.0 moles. So the answer is 1.0 moles NaOH.--- Example 3: How many moles of silver nitrate (AgNO3) are needed to make 3.7 liters of 0.43 M AgNO3 solution?--- Answer: Same as before, but the math is more complicated. In 1 liter, there are 0.43 moles, so in 3.7 liters, there are 0.43 * 3.7 = 1.591 moles.Now we can't measure moles directly, so we need to find the number of grams of the solute so we can weigh it out. Once we've found the number of moles, we can convert that to grams from the molar mass of the substance (or atomic mass of the element). We need the periodic table for this (see the link below for a periodic table). Again, let me illustrate with a couple of examples. In fact I'll use the same examples as before.--- Example 1: How many grams of LiCl are needed to make 1 liter of 0.5 M LiCl?--- Answer: From before we figured out that we need 0.5 moles of LiCl. So how many grams is that? We first need to calculate the molar mass of LiCl. From the periodic table, the atomic weight of lithium (Li) is 6.941 grams per mole and the weight of chlorine (Cl) is 35.453 grams per mole. So the atomic mass of LiCl is: 6.941 + 35.453 = 42.394 grams per mole. So if we need 0.5 moles, than to find the grams, we just multiply: 0.5 moles * 42.394 grams/mole = 21.197 grams So, to make 1 liter of 0.5 M LiCl, we need to add 21.197 grams of HCl and add enough water to make the total volume equal 1 liter.--- Example 2: How many NaOH are need to make 2 liters of 0.5 M NaOH?--- Answer: From before, we know we need 1 mole of NaOH. The molar mass of NaOH is equal to: 22.9898 + 15.999 + 1.0079 = 39.9967 grams per mole So since we need 1 mole, we add 39.9967 grams of NaOH and add water until we have a total of 2 liters of solution.--- Example 3: How many grams of AgNO3 are needed to make 3.7 liters of 0.43 M acetic acid solution?--- Answer: Again, from before we know we need 1.591 moles of AgNO3. To find the number of grams, we must find the molar mass. So the molar mass of AgNO3 is: 107.868 + 14.007 + (3*15.999) = 169.873 g/mole So to find the number of grams, we just multiply: 1.591 moles * 169.873 g/mole = 270.268 grams. So we must add 270.268 grams of acetic acid, and then add enough water to make the total volume 3.7 liters. (Of course, that'd be really very expensive because silver nitrate is not cheap, and that a lot of it!)TO SUMMARIZE HOW TO MAKE A SOLUTION:1) From the concentration and the volume given to you in the problem, first find the number of moles of solute:Moles of solute = Concentration * Volume (or moles = molarity * liters)2) Then convert moles to grams using the molar mass:Number of grams = Number of moles * Molar mass (or grams = moles grams per mole)3) Then add water to the solid until the TOTAL volume of the solution is the correct amount you need.


How many grams of NaOH do you need to make 1 liter of a 10 percent sodium hudroxide solution?

To make a 10% NaOH solution, you would need 100 grams of NaOH per liter of water. So to make 1 liter, you would need 100 grams of NaOH.


How many grams of sodium metabisulphite is needed to make 0.01N solution?

To prepare a 0.01N solution of sodium metabisulfite, you would need 2.31 grams of sodium metabisulfite per liter of solution.


How many grams of sodium metabisulfite is needed to make 10 percent solution?

Put 100 grams in a beaker and and around 500 mls of water until it dissolves, then top up the beaker to a liter. That is your 10% solution. The percentage solution is a ratio of the weight of the compound to the weight of the final solution.


How many grams of NaCl would you use to make 100ml of a 4M solution?

The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl


How many grams of hydrochloric acid are needed to make a solution of 2 molar?

To make a 2 molar solution of hydrochloric acid, you would need to know the volume of the solution you want to make. Once you have the volume, you can use the molarity formula (M = moles of solute / liters of solution) to calculate the grams of hydrochloric acid needed.


What exactly how would you make 100 grams of a saltwater solution that is 20 percent salt tell how many grams of salt and how many grams of water you would need?

20% salt solution is the equivalent of adding 200gr salt in a 800 ml (1000ml -200ml) of water. you now have one liter of a 20% solution.


What is the mass of NH4CL that must be dissolved in 200 grams of water 50 degree celsius to make a saturated solution?

The solubility of NH4Cl in water at 50°C is approximately 74 grams per 100 grams of water. To make a saturated solution, you would need to dissolve 148 grams of NH4Cl in 200 grams of water.