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The answer is 0,526 mL.

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11y ago
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11y ago

You need 10 moles of acid (980,79 g).

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Q: What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4?
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How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?

Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.


How many moles of sodium chloride are needed to prepare 500 mL of a 0.250 M solution?

500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.


What is the molarity of a solution is defined as?

The concentration in moles of a substance in the solution


How do you find the concenration of a solution?

Concentration of a solution is recorded in molarity (M). Molarity is the moles of solute divided my liters of solution. So to find the concentration of a solution, calculate the number of moles of the solute (the chemical being dissolved) and measure the number of liters of the solution (the water), then divide them.


What term is defined as the number of moles of solute divides by the number of liters of solution?

This the molarity.


How many grams of CaCl2 are needed to prepare 2.00 l if 0.700 M CaCl2 solution?

The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.


What is the total number of moles of solute in 2.0 liters of 3.0 M NaOH?

I believe the molarity is 1. molarity = number of moles / liters of solution molarity = 3 / 3 = 1


What is the molarity of a solution of 3 moles if FeBr3 in one half L water?

Molarity = number of moles / number of liters. For this question the number of moles is 3 and the number of liters is 0.5 So 3/0.5 = 6 The solution is 6 M.


How do you calculate the molarity of the solution composed of 2.60 grams of NaCl in a total volume of 35 mL of solution?

Molarity means the number of mol of a substance per 1 litre of substance. Or figure out the number of mol of NaCl ((2.60/(23+35)=0.04) then multiply the 35ml by 28.571428 to get that to litres.. then multiply the number of mol by 28.571428 to get that to the number of mol. Therefore the answer is 1.142857M. See the Related Questions link "How do you prepare a solution of a specific concentration?"


How do you find the amount of precipitate in a saturated solution?

first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles. first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles.


How do you determine the molarity of a solution containing 18.2g C6H12O6and enough water to reach 6.3L?

Moles of solute ---------------- Liters of solution So, convert your grams to moles by dividing by the molar mass (add together the atomic masses of the solution) and then that will give you your moles. Divide that number by your 6.3 Liters. That number is your molarity.


A solution of 30 percent acid and a solution of 60 percent acid are to be mixed to produce 50 liters of 57 percent acid How many liters of each solution should be used?

t = number of liters of 30% acid solution s = number of liters of 60% acid solution t+s=57 .30t+.60s=.50*57 t=57-s .30(57-s)+.60s=.50*57 .30*57 -.30s +.60s = .50*57 .30s = .50*57 - .30*57 = .20*57 s = .20*57/.30 = 38 liters of 30% solution t = 57 - s = 57-38 = 19 liters of 60% solution