I believe the molarity is 1.
molarity = number of moles / liters of solution
molarity = 3 / 3 = 1
6 moles.
Work:
2-Molar solution = X (solute) / 3 liters (solution)
2(3) = 6
X=6
The total number of moles of solute in 2.0 liters of 3.0 M NaOH is 6 moles NaOH.
One: molarity = solute/solution in liters.
1
Molarity = Mols of solute / L of solution total
The number of moles of a solute per kilogram of solvent. (Apex)
The total number of moles of a solute, regardless of state, in one liter of solution. Given as moles/L.
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
The answer is 0,526 mL.
This is the molar fraction.
Molarity = Mols of solute / L of solution total
The number of moles of a solute per kilogram of solvent. (Apex)
The total number of moles of a solute, regardless of state, in one liter of solution. Given as moles/L.
The three main ways are: molarity (M) = moles solute/liters solution; molality (m) = moles solute/kilograms solvent; mole fraction = moles 1 component/total moles all components. There's also percent by volume, percent by mass, and normality.
Molarity = moles solute/liters solution = 0.207 moles/0.1665 L = 1.24 molar (3 sig. figs.)
molal = m = moles solute/kg solvent. Assuming water as the solvent 1 kg = 1000 g/18g/mole = 55.56 moles H2O. Moles solute = 3.71 moles. Total moles present = 55.56 + 3.71 = 59.27 moles.Mole fraction solute = 3.71/59.27 = 0.0626
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
The answer is 0,526 mL.
Molarity of a solution is the number of moles of the solute divided by the volume of the solution (in liters). If 750 ml of 20M HCl is mixed with 250 ml of 60M HCl, we first find the total number of moles of HCl in our new solution. Using that same formula, M=moles/V, we cansee that moles=MV. In the first solution we have (20M)(0.750L) = 15 moles. In the second, (60M)(0.250L) = 15 moles, so we have a total of 30 moles in our new solution, which also has a volume of 750mL + 250mL = 1L. The molarity of the new solution is 30 moles/1L = 30M
In science, concentration is the number of moles of solute divided by the total volume of the solution (not just the volume of the solvent). Concentration units can also include the percentage solute to the total mass of the solution; the parts per million, ppm of the solute compared to the total parts present.