First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:
molality (m) = (moles of solute) / (total volume of solution (in liters))
To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:
moles solute = (molality)(total volume of solution)
Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.
***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mL
moles NaOH = (125 m)(0.500 L) = 62.5 moles
Finally, convert this to grams by finding the molar mass of NaOH using the Periodic Table:
22.99 + 16.00 + 1.008 = 39.998 g/mol
62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
Molarity = moles of solute/Liters of solution (250 ml = 0.250 L)
get moles NaOH
0.5 M NaOH = X Moles NaOH/0.250 Liters
= 0.125 moles NaOH
===================now, find grams NaOH
0.125 moles NaOH (39.998 grams/1 mole NaOH)
= 5 grams NaOH needed
==================
First.
Molarity = moles of solute/Liters of solution ( 500 mL = 0.5 L )
0.5 M NaOH = X moles/0.5 L
= 0.25 moles NaOH
----------------------------
Second.
0.25 moles NaOH (39.998 grams/1 mole NaOH)
= 10 grams NaOH
=============
To prepare this solution, 0.080 mol of NaOH is needed, hence it is 0.080 x 40 = 3.200 grams.
2.5g
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
The answer is 59,967 grams.
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
1280 grams
I think you may have missed a decimal point somewhere. 125M of NaOH would be a solution of sodium hydroxide containing 125 moles per litre. One mole of a compound is the same number of grams as the molecular weight of the molecule. Sodium hydroxide has a molecular weight of 40 ( sodium 23, oxygen 16, and hydrogen 1), so a one molar solution would have forty grams of NaOH per litre. 500ml of a 1M solution would contain 20g. 500ml of a 125M solution would need 2 500g. 1L of a 125M solution would need 5 000g of sodium hydroxide in the litre. The maximum solubility for NaOH in water at 20 degrees is 1110g per litre, so if you tried to dissolve 5 000g in a litre you would be left with 3 890g undissolved. A 1.25M solution would have 1.25 times 40g per litre, which is 50g per litre. 500ml of this solution would have half this amount of NaOH, or 25g.
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
208g NaOH
The answer is 59,967 grams.
Molecular mass of NaOH= 40.0 grams9.40 grams / (40.0 grams) = .235 moles NaOH
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
1280 grams
I think you may have missed a decimal point somewhere. 125M of NaOH would be a solution of sodium hydroxide containing 125 moles per litre. One mole of a compound is the same number of grams as the molecular weight of the molecule. Sodium hydroxide has a molecular weight of 40 ( sodium 23, oxygen 16, and hydrogen 1), so a one molar solution would have forty grams of NaOH per litre. 500ml of a 1M solution would contain 20g. 500ml of a 125M solution would need 2 500g. 1L of a 125M solution would need 5 000g of sodium hydroxide in the litre. The maximum solubility for NaOH in water at 20 degrees is 1110g per litre, so if you tried to dissolve 5 000g in a litre you would be left with 3 890g undissolved. A 1.25M solution would have 1.25 times 40g per litre, which is 50g per litre. 500ml of this solution would have half this amount of NaOH, or 25g.
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
The formula mass of sodium hydroxide, NaOH is 23.0+16.0+1.0=40.0 Amount of NaOH in 25.0g sample = 0.625mol
how many grams are contained in 11.89 pounds?
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
This solution contain 26,3 g NaOH.